android listview onTouch和onItemClick并存

问题：根据手指是滑动还是单击，决定触发onTouch还是onItemClick。。滑动触发onTouch事件，单击触发onItemClick事件。。

解决：根据onTouch返回的值判断，如果返回true，不触发onItemClick。返回false，则触发onItemClick。在onTouch中会依次触发down，move，up操作。。所以可以在up里面判断，如果移动距离=0，就是单击了，返回false，触发onItemClick。如果移动距离！=0，就返回true。

/**
* 根据手指滑动，控件做出相应的滑动
*
* @param event
* @return
*/
public boolean onMove(MotionEvent event) {
RelativeLayout.LayoutParams layoutParams = (RelativeLayout.LayoutParams) content.getLayoutParams();
boolean result = false;
switch (event.getAction()) {
case MotionEvent.ACTION_UP:
float upX = event.getX();
System.out.println("--我移动了" + moveX + "距离--");
<span style="color:#ff0000;">if ((upX - downX) != 0) {</span>
if (layoutParams.leftMargin > MAX_WIDTH / 2) { //滑动不到一半距离，缩回
new AsynMove().execute(SPEED);
} else {
new AsynMove().execute(-SPEED);
}
<span style="color:#ff0000;">result = true;</span> // 存在滑动距离，不触发item点击事件。。
<span style="color:#ff0000;">} else {
result = false;
}</span>
break;
case MotionEvent.ACTION_DOWN: // 单击
System.out.println("我在单击，返回false，进入item点击事件");
downX = event.getX();
result = false;
break;
case MotionEvent.ACTION_MOVE:
moveX = event.getX() - downX;
layoutParams.leftMargin += moveX;
layoutParams.rightMargin -= moveX;
if (layoutParams.leftMargin <= 0) { //设置最小值和最大值，使之不会滑动过了头
layoutParams.leftMargin = 0;
layoutParams.rightMargin = 0;

} else if (layoutParams.leftMargin >= MAX_WIDTH) {
layoutParams.leftMargin = MAX_WIDTH;
layoutParams.rightMargin = -MAX_WIDTH;
}
System.out.println("--我在滑动-leftMargin: " + layoutParams.leftMargin + " rightMargin: " + layoutParams.rightMargin);
result = true;
break;
}
content.setLayoutParams(layoutParams);
return result;
}