java 删除字符串中的特定字符

/**
* Delete any character in a given String.
* @param inString the original String
* @param charsToDelete a set of characters to delete.
* E.g. "az\n" will delete 'a's, 'z's and new lines.
* @return the resulting String
*/
public static String deleteAny(String inString, String charsToDelete) {
if (!hasLength(inString) || !hasLength(charsToDelete)) {
return inString;
}
StringBuilder sb = new StringBuilder();
for (int i = 0; i < inString.length(); i++) {
char c = inString.charAt(i);
if (charsToDelete.indexOf(c) == -1) {
sb.append(c);
}
}
return sb.toString();
}
/**
* Check that the given String is neither {@code null} nor of length 0.
* Note: Will return {@code true} for a String that purely consists of whitespace.
* @param str the String to check (may be {@code null})
* @return {@code true} if the String is not null and has length
* @see #hasLength(CharSequence)
*/
public static boolean hasLength(String str) {
return hasLength((CharSequence) str);
}
/**
* Check that the given CharSequence is neither {@code null} nor of length 0.
* Note: Will return {@code true} for a CharSequence that purely consists of whitespace.
* <p><pre class="code">
* StringUtils.hasLength(null) = false
* StringUtils.hasLength("") = false
* StringUtils.hasLength(" ") = true
* StringUtils.hasLength("Hello") = true
* </pre>
* @param str the CharSequence to check (may be {@code null})
* @return {@code true} if the CharSequence is not null and has length
* @see #hasText(String)
*/
public static boolean hasLength(CharSequence str) {
return (str != null && str.length() > 0);
}