[LeetCode] Minimum Depth of Binary Tree 二叉树的最小深度

Given a binary tree, find its minimum depth.

The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node.

二叉树的经典问题之最小深度问题就是就最短路径的节点个数，还是用深度优先搜索DFS来完成，万能的递归啊。。。请看代码：

/**
* Definition for binary tree
* struct TreeNode {
*     int val;
*     TreeNode *left;
*     TreeNode *right;
*     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
int minDepth(TreeNode *root) {
if (root == NULL) return 0;
if (root->left == NULL && root->right == NULL) return 1;

if (root->left == NULL) return minDepth(root->right) + 1;
else if (root->right == NULL) return minDepth(root->left) + 1;
else return 1 + min(minDepth(root->left), minDepth(root->right));
}

};

求二叉树的最大深度可以参见我的博文：

/article/4901521.html

LeetCode All in One 题目讲解汇总(持续更新中...)