leetcode:Reverse Integer【Python版】
2014-10-18 22:16
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1、在进入while之前,保证x是非负的;
2、符号还是专门用flag保存
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3、另一思路:将integer转换成string,然后首位swap,直至中间;
2、符号还是专门用flag保存
===================
3、另一思路:将integer转换成string,然后首位swap,直至中间;
class Solution: # @return an integer def reverse(self, x): ret = 0 flag = 1 if x < 0: flag = -1 x *= -1 while(x!=0): ret = ret*10+x%10 x = x/10 return ret*flag
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