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What is the difference between Initializing and Assignment inside a constructor?

2014-10-10 16:22 489 查看
http://stackoverflow.com/questions/1711990/what-is-this-weird-colon-member-syntax-in-the-constructor

Foo(int num): bar(num)


This construct is called a Member Initializer List in C++.

Simply said, it initializes your member
bar
to
a value
num
.


What is the difference between Initializing and Assignment inside a constructor?

Member Initialization:
Foo(int num): bar(num) {};


Member Assignment:
Foo(int num)
{
bar = num;
}


There is a significant difference between Initializing a member using Member initializer list and assigning it an value inside the constructor body.

When you initialize fields via Member initializer
list the constructors will be called once and the object will be constructed and initialized in one operation.

If you use assignment then the fields will be
first initialized with default constructors and then reassigned (via assignment operator) with actual values.

As you see there is an additional overhead of creation & assignment in the latter, which might be considerable for user defined classes.
Cost of Member Initialization = Object Construction
Cost of Member Assignment = Object Construction + Assignment


The latter is actually equivalent to:
Foo(int num) : bar() {bar = num;}


While the former is equivalent to just:
Foo(int num): bar(num){}


For an inbuilt (your code example) or POD class members there is no practical overhead.


When do you HAVE TO use Member Initializer list?

You will have(rather forced) to use a Member Initializer list if:

Your class has a reference member

Your class has a non static const member or

Your class member doesn't have a default constructor or

For initialization of base class members or

When constructor’s parameter name is same as data member(this is not really a MUST)


A code example:

class MyClass
{
public:
//Reference member, has to be Initialized in Member Initializer List
int &i;
int b;
//Non static const member, must be Initialized in Member Initializer List
const int k;

//Constructor’s parameter name b is same as class data member
//Other way is to use this->b to refer to data member
MyClass(int a, int b, int c):i(a),b(b),k(c)
{
//Without Member Initializer
//this->b = b;
}
};

class MyClass2:public MyClass
{
public:
int p;
int q;
MyClass2(int x,int y,int z,int l,int m):MyClass(x,y,z),p(l),q(m)
{
}

};

int main()
{
int x = 10;
int y = 20;
int z = 30;
MyClass obj(x,y,z);

int l = 40;
int m = 50;
MyClass2 obj2(x,y,z,l,m);

return 0;
}


MyClass2
doesn't
have a default constructor so it has to be initialized through member initializer list.

Base class
MyClass
does
not have a default constructor, So to initialize its member one will need to use Member Initializer List.

Online
version of code sample.


Important points to Note while using Member Initializer Lists:

Class Member variables are always initialized in the order in which they are declared in the class.

They are not initialized in the order in which they are specified in the Member Initalizer List.

In short, Member initialization list does not determine the order of initialization.

Given the above it is always a good practice to maintain the same order of members for Member initialization as the order in which they are declared in the class definition. This is because compilers do not warn if the two orders are different but a relatively
new user might confuse member Initializer list as the order of initialization and write some code dependent on that.

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