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leetcode —— single number

2014-09-11 13:47 190 查看
Given an array of integers, every element appears twice except for one. Find that single one.

Note:

Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

class Solution {
public:
int singleNumber(int A[], int n) {
int number=A[0];
for (int i=1;i<n;++i)
{
number=number^A[i];

}
return number;

}
};
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