Python在嵌套函数内部访问并父级函数的变量

主要来自stackoverflow上的解答http://stackoverflow.com/questions/6198709/how-do-i-change-nesting-functions-variable-in-the-nested-function

def accessVarFromNestedFunc():
localVarInParent = [1]; #here just define a list, first value is what we want to use

def nestedFunc(): #
localVarInParent[0] = localVarInParent[0] + 1 ; # localVarInParent[0] is the first value of above list value: localVarInParent, and its initial value is 1
print "In nested func, localVarInParent[0]=",localVarInParent[0];#2,3,4,5,6

for i in range(5):
nestedFunc();
# here can got value is 6, which is changed after nested function
print "In current parent nesting func, localVarInParent[0]=",localVarInParent[0]; #In current parent nesting func, localVarInParent[0]= 6

if __name__ == "__main__":
accessVarFromNestedFunc();

也即：

Python中，嵌套函数内部去操作被嵌套的父级函数中的变量的话：

Python 2.x：把变量弄进一个列表中的第1个值，index=0，然后就可以在嵌套函数中，获得该list列表变量，操作其中第1个值了。

Python 3.x：把变量定义为nonlocal即可。