HDU1429胜利大逃亡(续)&&HDU 1885 Key Task BFS+状态压缩+水

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <limits.h>
#include <malloc.h>
#include <ctype.h>
#include <math.h>
#include <string>
#include <iostream>
#include <algorithm>
using namespace std;
#define MAXN 11111
#include<queue>
const int INF = 999999;
char mp[33][33];
bool vis[33][33][1026];
int n,m;
struct node
{
int x,y,step;
int key;
};
queue<node>q;
int xx[4]= {1,0,-1,0};
int yy[4]= {0,1,0,-1};
int bfs(int x,int y)
{
while(!q.empty())
q.pop();
memset(vis,false,sizeof(vis));
node front,rear;
front.x=x,front.y=y;
front.key=0;
front.step=0;
vis[x][y][0]=true;
q.push(front);
while(!q.empty())
{
front=q.front();
q.pop();
for(int i=0; i<4; i++)
{
int dx=front.x+xx[i],dy=front.y+yy[i];
if(dx>=0&&dy>=0&&dx<n&&dy<m&&mp[dx][dy]!='*'&&!vis[dx][dy][front.key])
{
if(mp[dx][dy]=='^')//到终点
{
return front.step+1;
}
else if(mp[dx][dy]>='a'&&mp[dx][dy]<='z')//拿到钥匙
{
vis[dx][dy][front.key]=true;//标记
rear.key =(front.key )| ( 1<<(mp[dx][dy]-'a'));//添加钥匙
rear.x=dx,rear.y=dy,rear.step=front.step+1;
q.push(rear);
}
else if(mp[dx][dy]>='A'&&mp[dx][dy]<='Z')//遇到门
{
if(front.key&(1<<(mp[dx][dy]-'A')))//如果有对应的钥匙
{
rear.x=dx,rear.y=dy,rear.key=front.key,rear.step=front.step+1;
vis[dx][dy][rear.key]=true;
q.push(rear);
}
}
else
{
rear.x=dx,rear.y=dy,rear.key=front.key,rear.step=front.step+1;
vis[dx][dy][rear.key]=true;
q.push(rear);
}
}
}
}
return 0;
}
int main()
{
int t;
//  freopen("in.txt","r",stdin);
while(scanf("%d%d%d",&n,&m,&t)!=EOF)
{
node s;
for(int i=0; i<n; i++)
scanf("%s",mp[i]);
for(int i=0; i<n; i++)
{
for(int j=0; j<m; j++)
{
if(mp[i][j]=='@')
s.x=i,s.y=j,s.step=0;
}
}
int ans=bfs(s.x,s.y);
if(ans==0||ans>=t)
printf("-1\n");
else printf("%d\n",ans);
}
return 0;
}

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <limits.h>
#include <malloc.h>
#include <ctype.h>
#include <math.h>
#include <string>
#include <iostream>
#include <algorithm>
using namespace std;
#define MAXN 11111
#include<queue>
const int INF = 999999;
char mp[133][133];
bool vis[133][133][33];
int n,m;
int ke[28];
struct node
{
int x,y,step;
int key;
};
queue<node>q;
int xx[4]= {1,0,-1,0};
int yy[4]= {0,1,0,-1};
int bfs(int x,int y)
{
while(!q.empty())
q.pop();
memset(vis,false,sizeof(vis));
node front,rear;
front.x=x,front.y=y;
front.key=0;
front.step=0;
vis[x][y][0]=true;
q.push(front);
while(!q.empty())
{
front=q.front();
q.pop();
for(int i=0; i<4; i++)
{
int dx=front.x+xx[i],dy=front.y+yy[i];
if(dx>=0&&dy>=0&&dx<n&&dy<m&&mp[dx][dy]!='#'&&!vis[dx][dy][front.key])
{
if(mp[dx][dy]=='X')//到终点
{
return front.step+1;
}
else if(mp[dx][dy]>='a'&&mp[dx][dy]<='z')//拿钥匙
{
vis[dx][dy][front.key]=true;
rear.key =(front.key )| ( 1<<(ke[mp[dx][dy]-'a']));
rear.x=dx,rear.y=dy,rear.step=front.step+1;
q.push(rear);
}
else if(mp[dx][dy]>='A'&&mp[dx][dy]<='Z')//开门
{
if(front.key&(1<<(ke[mp[dx][dy]-'A'])))
{
rear.x=dx,rear.y=dy,rear.key=front.key,rear.step=front.step+1;
vis[dx][dy][rear.key]=true;
q.push(rear);
}
}
else
{
rear.x=dx,rear.y=dy,rear.key=front.key,rear.step=front.step+1;
vis[dx][dy][rear.key]=true;
q.push(rear);
}
}
}
}
return 0;
}
int main()
{
//freopen("in.txt","r",stdin);

ke['a'-'a']=0,ke['b'-'a']=1,ke['r'-'a']=2,ke['g'-'a']=3;
while(scanf("%d%d",&n,&m),n+m)
{
node s;
for(int i=0; i<n; i++)
scanf("%s",mp[i]);
for(int i=0; i<n; i++)
{
for(int j=0; j<m; j++)
{
if(mp[i][j]=='*')
s.x=i,s.y=j,s.step=0;
}
}
int ans=bfs(s.x,s.y);
if(ans==0)
printf("The poor student is trapped!\n");
else printf("Escape possible in %d steps.\n",ans);
}
return 0;
}