您的位置:首页 > 其它

(leetcode 1)Reverse Words in a String

2014-06-08 10:39 330 查看
Given an input string, reverse the string word by word.

For example,

Given s = "
the sky
 is blue
",

return "
blue is sky
 the
".

click to show clarification.

Clarification:

What constitutes a word?

A sequence of non-space characters constitutes a word.
Could the input string contain leading or trailing spaces?

Yes. However, your reversed string should not contain leading or trailing spaces.
How about multiple spaces between two words?

Reduce them to a single space in the reversed string.

void reverseWords(string &s) {
        if(s=="")
        return;
    int i = s.size()-1,flagL,flagR;
    string tmp = "";
    for(; i >= 0; i--)
    {
        while(i >= 0 && ' '== s[i])i--;
        flagR = i; //从右开始找到第一个不是 “  ” 的字符位置
        while(i >= 0 && ' '!= s[i])i--;
        flagL = i+1;//从右向左开始找到第二个不是 “  ” 的字符位置
        if(flagL>=0&&flagR>=0)
            tmp += s.substr(flagL,flagR-flagL+1)+" ";
    }
        s = tmp;
        if(s.size()>1)
            s.erase(s.size()-1,1);
    }
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: