可访问类型不一致：参数类型的Vector比运算符operator +的（Vector，Vector）的可访问性低的解决方法

C#中第一个问题：参数类型的Vector比运算符operator +的（Vector，Vector）的可访问性低

namespace testVS10
{
class Program
{
public struct Vector {
public double x, y, z;
public Vector(double x, double y, double z) {
this.x = x;
this.y = y;
this.z = z;
}
public Vector(Vector rhs) {
x = rhs.x;
y = rhs.y;
z = rhs.z;
}
public override string ToString()
{
return "(" + x +","+ y + "," + z +")";
}
}
public static Vector operator + (Vector lhs, Vector rhs)
{
Vector result = new Vector(lhs);
result.x += rhs.x;
result.y += rhs.y;
result.z += rhs.z;
return result;

}

static void Main()
{
Vector vect1, vect2, vect3;
vect1 = new Vector(4.0, 5.0, 3.0);
vect2 = new Vector(4.0, 2.0, 7.0);
vect3 = vect1 + vect2;
Console.WriteLine("vect1 =" + vect1.ToString);
Console.WriteLine("vect2 =" + vect2.ToString);
Console.WriteLine("vect3 =" + vect3.ToString);
}
}
}

加上public之后这个问题就解决了，原因是没加public，C#在类中中声明的变量默认是private。

解决这个问题之后还有一个问题是：二元运算符的参数之一必须是包含类型。operator +是有问题的。