Coder-Strike 2014 - Round 1 D. Giving Awards
2014-04-19 21:57
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题目链接:
http://codeforces.com/contest/412/problem/D
题目大意:
给n个人发工资,但是因为ai欠bi钱,所以要避免ai后面是bi领工资。
思路:
利用dfs,遍历每个人的后继关系(后面的人欠前面的人钱),直到一个人后继无人(好别扭。。),就把他加入答案队列中。
AC代码:
http://codeforces.com/contest/412/problem/D
题目大意:
给n个人发工资,但是因为ai欠bi钱,所以要避免ai后面是bi领工资。
思路:
利用dfs,遍历每个人的后继关系(后面的人欠前面的人钱),直到一个人后继无人(好别扭。。),就把他加入答案队列中。
AC代码:
#include<cstdio> #include<vector> using namespace std; const int M = 3e4 + 20; vector<int> v[M]; int ans[M], cnt; bool vis[M]; void dfs(int a) { if(vis[a]) return ; vis[a] = true; for(int i = 0; i < v[a].size(); i++) dfs(v[a][i]); ans[cnt++] = a; } main() { int n, k; scanf("%d %d", &n, &k); while(k--) { int a, b; scanf("%d %d", &a, &b); v[a].push_back(b); } for(int i = 1; i <= n; i++) { if(vis[i]) continue; dfs(i); } for(int i = 0; i < cnt; i++) printf("%d ", ans[i]); }
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