python类库[使用xml.etree.ElementTree读写xml]


一 基本知识

1、插入节点

Element.insert(index, element) 、Element(tag[, attrib][, **extra]) 、SubElement(parent,
tag[, attrib[, **extra]]) 、Element.append(subelement)

2、删除节点

Element.remove(subelement) 删除一个节点、Element.clear()删除该节点下所有子节点

3、在节点中插入属性

Element.set(key, value)
4、查找节点
a) Element.getiterator b) Element.getchildren c) Element.find d) Element.findall

二 读取xml
1）xml为

<?xml version="1.0" encoding="UTF-8"?>

<employees>

<employee id = '1'>

<name>linux</name>

<age>30</age>

</employee>

<employee id = '2'>

<name>windows</name>

<age>20</age>

</employee>

</employees>

2）python脚本为

from xml.etree import ElementTree

def print_node(node):

print "====================================="

for key,value in node.items():

print "%s:%s" % (key, value)

for subnode in node.getchildren():

print "%s:%s" % (subnode.tag, subnode.text)

def read_xml(text = '', xmlfile = ''):

#root = ElementTree.parse(xmlfile)

root = ElementTree.fromstring(text)

# 1 getiterator([tag=None])

# only elements whose tag equals tag are returned from the iterator

eitor = root.getiterator("employee")

for e in eitor:

print_node(e)

# 2 getchildren()

# Returns all subelements

eitor = root.getchildren()

for e in eitor:

print_node(e)

# 3 findall(match)

# Finds all subelements matching match.

# match may be a tag name or path. Returns an iterable yielding all matching elements

node_findall = root.findall("employee")

for e in node_findall:

print_node(e)

# 4 find(match)

# Finds the first subelement matching match.

# match may be a tag name or path. Returns an element instance or None

node_find = root.find('employee')

print_node(node_find)

if __name__ == '__main__':

read_xml(open("employees.xml").read())

参考：
http://blog.csdn.net/kiki113/archive/2009/04/06/4052584.aspx

完！