python 使用 signal模块实现函数调用超时问题

#coding=utf-8
import signal
import time
class TimeOutException(Exception):
pass

def setTimeout(num, callback):
def wrape(func):
def handle(signum, frame):
raise TimeOutException("运行超时！")
def toDo(*args, **kwargs):
try:
signal.signal(signal.SIGALRM, handle)
signal.alarm(num)#开启闹钟信号
rs = func(*args, **kwargs)
signal.alarm(0)#关闭闹钟信号
return rs
except TimeOutException, e:
callback()

return toDo
return wrape

if __name__ == '__main__':

def doSome():
print "lij"

@setTimeout(4,doSome )
def getName():
time.sleep(10)
return ["A", "B", "C"]

s = getName()
print s