OpenJudge/Poj 1517 u Calculate e

总时间限制:1000ms内存限制:65536kB描述A simple mathematical formula for e is
e=Σ0<=i<=n1/i!
where
n is allowed to go to infinity. This can actually yield very accurate
approximations of e using relatively small values of n.输入No input输出Output the approximations of e generated by the above formula for
the values of n from 0 to 9. The beginning of your output should appear
similar to that shown below.样例输入

no input

样例输出

n e
- -----------
0 1
1 2
2 2.5
3 2.666666667
4 2.708333333
...

来源Greater New York 2000

#include "stdio.h"
//#include "stdlib.h"
int main()
{
int tmp=1;
double sum=1;
int i=0;
printf("n e\n");
printf("- -----------\n");
printf("%d %.10g\n",i,sum);
for(i=1;i<10;i++)
{
tmp*=i;
sum+=(double)1/tmp;
printf("%d %.10g\n",i,sum);
}
//system("pause");
return 0;
}