lua杂项

luafor里面v = nil无效

--[[
local test01 =
{
	[1] = {{1,2,3,4},{1,2,3,4}},
	[2] = {{1,2,3,4},{1,2,3,4}},
}
for k,v in pairs(test01)do
	for kk,vv in pairs(v)do
		if(kk == 1)then
			test01[k][kk] = nil
		end
	end
end
--test01[1][1] = nil
print(GetCount(test01[1]))
]]

lua 取整 取余

使用math.modf(x/y),此函数,第一参数返回整数部分,第二个参数返回小数部分

lua获得时分秒

function todate()
	local t=os.date("*t",os.time())
	return t["hour"],t["min"], t["sec"]
end
print(todate())

lua字符串合并

local a = 1
local b = ","
local c = 2
local str = tostring(a)..tostring(b)..tostring(c)
print(str)

lua 类型转换

string to int
tonumber
print(tonumber("1234"))

lua分割字符串

function FGUtilStringSplit(str,split_char)
	-------------------------------------------------------
	-- 参数:待分割的字符串,分割字符
	-- 返回:子串表.(含有空串)
	local sub_str_tab = {};
	while (true) do
		local pos = string.find(str, split_char);
		if (not pos) then
			sub_str_tab[#sub_str_tab + 1] = str;
			break;
		end
		local sub_str = string.sub(str, 1, pos - 1);
		sub_str_tab[#sub_str_tab + 1] = sub_str;
		str = string.sub(str, pos + 1, #str);
	end
	return sub_str_tab;
end

lua continue

for i = 1, 10 do
    repeat
        if i == 5 then
            break
        end
        print(i)
    until true
end

lua 中pairs 和 ipairs区别

http://blog.csdn.net/witch_soya/article/details/7556595

lua与c++的结合

http://blog.csdn.net/favormm/article/details/5796587

http://www.cnblogs.com/osyun/tag/tolua/