C++面向对象类的实例题目七
2014-01-01 11:30
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题目描述:
编写两个有意义的类,使一个类嵌套在另一个类中。
分析:
本题涉及两个类student和cdegree,前者为学生类,包含学生的学号(nubner),姓名(name)和成绩(degree),而成绩degree是类cdegree的对象。cdegree类有3个数据成员,分别为数学(math),英语(english)和物理(phy)分数。
程序代码:
#include<iostream>
#include<string>
using namespace std;
class Student
{
public:
void getdata();
void showdata();
private:
string number;
string name;
class Cdegree
{
public:
double math;
double english;
double phy;
}degree;
};
void Student::getdata()
{
cout<<"Input number:";
cin>>number;
cout<<"Input name:";
cin>>name;
cout<<"Input degree of math:";
cin>>degree.math;
cout<<"Input degree of english:";
cin>>degree.english;
cout<<"Input degree of physics:";
cin>>degree.phy;
}
void Student::showdata()
{
cout<<"=========分割线======="<<endl;
cout<<"Number:"<<number<<endl;
cout<<"Name:"<<name<<endl;
cout<<"Math"<<degree.math<<endl;
cout<<"English:"<<degree.english<<endl;
cout<<"Physics:"<<degree.phy<<endl;
}
int main()
{
Student s1;
s1.getdata();
s1.showdata();
return 0;
}
结果输出:
Input number:007
Input name:qianshou
Input degree of math:89
Input degree of english:99
Input degree of physics:100
=========分割线=======
Number:007
Name:qianshou
Math89
English:99
Physics:100
编写两个有意义的类,使一个类嵌套在另一个类中。
分析:
本题涉及两个类student和cdegree,前者为学生类,包含学生的学号(nubner),姓名(name)和成绩(degree),而成绩degree是类cdegree的对象。cdegree类有3个数据成员,分别为数学(math),英语(english)和物理(phy)分数。
程序代码:
#include<iostream>
#include<string>
using namespace std;
class Student
{
public:
void getdata();
void showdata();
private:
string number;
string name;
class Cdegree
{
public:
double math;
double english;
double phy;
}degree;
};
void Student::getdata()
{
cout<<"Input number:";
cin>>number;
cout<<"Input name:";
cin>>name;
cout<<"Input degree of math:";
cin>>degree.math;
cout<<"Input degree of english:";
cin>>degree.english;
cout<<"Input degree of physics:";
cin>>degree.phy;
}
void Student::showdata()
{
cout<<"=========分割线======="<<endl;
cout<<"Number:"<<number<<endl;
cout<<"Name:"<<name<<endl;
cout<<"Math"<<degree.math<<endl;
cout<<"English:"<<degree.english<<endl;
cout<<"Physics:"<<degree.phy<<endl;
}
int main()
{
Student s1;
s1.getdata();
s1.showdata();
return 0;
}
结果输出:
Input number:007
Input name:qianshou
Input degree of math:89
Input degree of english:99
Input degree of physics:100
=========分割线=======
Number:007
Name:qianshou
Math89
English:99
Physics:100
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