python函数参数*args**kwargs用法实例

# 当函数的参数不确定时，可以使用*args和**kwargs。*args没有key值，**kwargs有key值

def fun_var_args(farg, *args):    print 'args:', farg    for value in args:        print 'another arg:',value

# *args可以当作可容纳多个变量组成的list或tuplefun_var_args(1, 'two', 3, None)

#args: 1#another arg: two#another arg: 3#another arg: None

def fun_var_kwargs(farg, **kwargs):    print 'args:',farg    for key in kwargs:        print 'another keyword arg:%s:%s' % (key, kwargs[key])

# myarg1,myarg2和myarg3被视为key， 感觉**kwargs可以当作容纳多个key和value的dictionaryfun_var_kwargs(1, myarg1='two', myarg2=3, myarg3=None)# 输出：#args: 1#another keyword arg:myarg1:two#another keyword arg:myarg2:3#another keyword arg:myarg3:None

def fun_args(arg1, arg2, arg3):    print 'arg1:', arg1    print 'arg2:', arg2    print 'arg3:', arg3

myargs = ['1', 'two', None]     # 定义列表fun_args(*myargs)

# 输出：#arg1: 1#arg2: two#arg3: None

mykwargs = {'arg1': '1', 'arg2': 'two', 'arg3': None}      # 定义字典类型fun_args(**mykwargs)

# 输出：#arg1: 1#arg2: two#arg3: None

# 两者都有def fun_args_kwargs(*args, **kwargs):    print 'args:', args    print 'kwargs:', kwargs

args = [1, 2, 3, 4]kwargs = {'name': 'BeginMan', 'age': 22}fun_args_kwargs(args,kwargs)# args: ([1, 2, 3, 4], {'age': 22, 'name': 'BeginMan'})# kwargs: {}

fun_args_kwargs(1,2,3,a=100)#args: (1, 2, 3)#kwargs: {'a': 100}

fun_args_kwargs(*(1,2,3,4),**{'a':None})#args: (1, 2, 3, 4)#kwargs: {'a': None}