解决Collection <__NSArrayM: 0xb550c30> was mutated while being enumerated.-
2013-09-22 17:03
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2013-09-22 16:45:42.229 ViewTest[2638:c07] *** Terminating app due to uncaught exception 'NSGenericException', reason: '*** Collection <__NSArrayM: 0xb550c30> was mutated while being enumerated.'
当程序出现这个提示的时候,是因为你一边便利数组,又同时修改这个数组里面的内容,导致崩溃,网上的方法如下:
这种方法就是在定义一个一模一样的数组,便利数组A然后操作数组B
今天终于找到了一个更快接的删除数组里面的内容以及修改数组里面的内容的方法:
NSMutableArray *tempArray = [[NSMutableArray
alloc]initWithObjects:@"12",@"23",@"34",@"45",@"56",
nil];
[tempArray enumerateObjectsUsingBlock:^(id obj,
NSUInteger idx, BOOL *stop) {
if ([obj isEqualToString:@"34"]) {
*stop = YES;
if (*stop == YES) {
[tempArray replaceObjectAtIndex:idx
withObject:@"3333333"];
}
}
if (*stop) {
NSLog(@"array is %@",tempArray);
}
}];
利用block来操作,根据查阅资料,发现block便利比for便利快20%左右,这个的原理是这样的:
找到符合的条件之后,暂停遍历,然后修改数组的内容
这种方法非常简单哟
当程序出现这个提示的时候,是因为你一边便利数组,又同时修改这个数组里面的内容,导致崩溃,网上的方法如下:
NSMutableArray * arrayTemp = xxx; NSArray * array = [NSArray arrayWithArray: arrayTemp]; for (NSDictionary * dic in array) { if (condition){ [arrayTemp removeObject:dic]; } }
这种方法就是在定义一个一模一样的数组,便利数组A然后操作数组B
今天终于找到了一个更快接的删除数组里面的内容以及修改数组里面的内容的方法:
NSMutableArray *tempArray = [[NSMutableArray
alloc]initWithObjects:@"12",@"23",@"34",@"45",@"56",
nil];
[tempArray enumerateObjectsUsingBlock:^(id obj,
NSUInteger idx, BOOL *stop) {
if ([obj isEqualToString:@"34"]) {
*stop = YES;
if (*stop == YES) {
[tempArray replaceObjectAtIndex:idx
withObject:@"3333333"];
}
}
if (*stop) {
NSLog(@"array is %@",tempArray);
}
}];
利用block来操作,根据查阅资料,发现block便利比for便利快20%左右,这个的原理是这样的:
找到符合的条件之后,暂停遍历,然后修改数组的内容
这种方法非常简单哟
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