2013网络赛成都赛区1003

2013 ACM/ICPC Asia Regional Chengdu Online problem1003

#include<stdio.h>
#include<string.h>
int main()
{
int i,t,tc;
char c[110];
scanf("%d",&t);
for(tc=1;tc<=t;tc++)
{
scanf("%s",c);
printf("Case #%d: ",tc);
for(i=0;i<strlen(c);i++)
{
if(c[i]=='d'&&c[i+1]=='e'&&c[i+2]=='s'
&&c[i+3]=='u'&&c[i+4]==0)
{
printf("nanodesu\n");
break;
}
else printf("%c",c[i]);
}
if(i==strlen(c))printf("nanodesu\n");
}
return 0;
}