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MVC中返回Json的几种声明方式

2013-05-19 03:06 369 查看

第一种，单行数据

var result = new { name = "linfei", age = "26", address = "wuhan" };

//MVC中返回
return Json(result);

//asp.net中返回
System.Web.Script.Serialization.JavaScriptSerializer js = new System.Web.Script.Serialization.JavaScriptSerializer();
return js.Serialize(result);

显示结果：

{
"name": "linfei",
"age": "26",
"address": "wuhan"
}

第二种，多行数据

var result = new object[] { new { name = "linfei", age = "22", address = "wuhan" }, new { name = "linfei", arg = "26", address = "sh" } };

//MVC中返回
return Json(result);

//asp.net中返回
System.Web.Script.Serialization.JavaScriptSerializer js = new System.Web.Script.Serialization.JavaScriptSerializer();
return js.Serialize(result);

显示结果：

[
{
"name": "linfei",
"age": "22",
"address": "wuhan"
},
{
"name": "linfei",
"arg": "26",
"address": "sh"
}
]

第三种，多行多对象数据

var data1 = new object[] { new { name = "linfei", age = "22", address = "wuhan" }, new { name = "linfei", arg = "26", address = "sh" } };
var data2 = new object[] { new { test="123",test1="qq"}, new { test = "456", test1 = "ww" } };
var result = new object[] { new { rows = data1 }, new { header = data2 } };
//MVC中返回
return Json(result);
//asp.net中返回
System.Web.Script.Serialization.JavaScriptSerializer js = new System.Web.Script.Serialization.JavaScriptSerializer();
return js.Serialize(result);

显示结果：

[
{
"rows": [
{
"name": "linfei",
"age": "22",
"address": "wuhan"
},
{
"name": "linfei",
"arg": "26",
"address": "sh"
}
]
},
{
"header": [
{
"test": "123",
"test1": "qq"
},
{
"test": "456",
"test1": "ww"
}
]
}
]

还有个asp.net中的写法，网上找的

var data1 = new object[] { new { name = "linfei", age = "22", address = "wuhan" }, new { name = "linfei", arg = "26", address = "sh" } };
var data2 = new object[] { new { test = "123", test1 = "qq" }, new { test = "456", test1 = "ww" } };
Newtonsoft.Json.JsonSerializerSettings settings = new Newtonsoft.Json.JsonSerializerSettings();
settings.ReferenceLoopHandling = Newtonsoft.Json.ReferenceLoopHandling.Ignore;
string result = Newtonsoft.Json.JsonConvert.SerializeObject(new { rows = data1, header = data2 }, Newtonsoft.Json.Formatting.Indented, settings);

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