Android 实现再按一次后退键退出应用程序

[java] view
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private boolean isexit = false;

private boolean hastask = false;

Timer texit = new Timer();

[java] view
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TimerTask task = new TimerTask() {

public void run() {

isexit = false;

hastask = true;

}

};



@Override

public boolean onKeyDown(int keyCode, KeyEvent event) {

if(keyCode == KeyEvent.KEYCODE_BACK && event.getAction() == KeyEvent.ACTION_DOWN){

//DialogAPI.showExit(this);

if(isexit == false){

isexit = true;

Toast.makeText(getApplicationContext(), "再按一次退出程序", Toast.LENGTH_SHORT).show();

if(!hastask) {

texit.schedule(task, 2000);

}

}else{

finish();

System.exit(0);

}

return false;

}



return super.onKeyDown(keyCode, event);

}

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