hdu 1237 简单计算器

#include<iostream>
#include<string.h>
using namespace std;
char a[205], c[205];
double b[205];

int main()
{
while(gets(a))
{
//if(!strcmp(a, "0"))
//	break;
memset(b, 0, sizeof(b));
memset(c, 0, sizeof(c));
int i, temp=0, t = 0, l;
l = strlen(a);
if(l == 1 && a[0] == '0')
{
exit(0);
}
double sum = 0;
for( i=0; i < l; i++ )
{
if(a[i] >= '0' && a[i] <= '9')
temp = temp*10 + a[i] - '0', b[t] = temp;
else
temp = 0;
if(a[i] == '+' || a[i] == '-' || a[i] == '*' || a[i] == '/')
c[t++] = a[i];
}
for( i=0; i < t; i++ )
{
if(c[i] == '*' || c[i] == '/')
{
if(c[i] == '*')
{
b[i+1] *= b[i];
b[i] = 0;
if(i-1 >= 0)
c[i] = c[i-1];
else
c[i] = '+';
}
else
{
b[i+1] = b[i] / b[i+1];
b[i] = 0;
if(i-1 >= 0)
c[i] = c[i-1];
else
c[i] = '+';
}
}
}

sum = b[0];
for( i=0; i < t; i++ )
{
if(c[i] == '+')
sum += b[i+1];
else
sum -= b[i+1];
}
printf("%.2lf\n", sum);
}

return 0;
}