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判断NSString是否为数字,以及转换为数字

2013-03-21 21:25 232 查看
当NSString为纯数字的时候可以用下面的方法:

//判断是否为整形:

- (BOOL)isPureInt:(NSString*)string{

NSScanner* scan = [NSScanner scannerWithString:string];

int val;

return[scan scanInt:&val] && [scan isAtEnd];

}

//判断是否为浮点形:

- (BOOL)isPureFloat:(NSString*)string{

NSScanner* scan = [NSScanner scannerWithString:string];

float val;

return[scan scanFloat:&val] && [scan isAtEnd];

}

更复杂点的Question:

I have an NSString like so:

@"200hello" or @"0 something"

What I would like to be able to do is take the first occuring number in the NSString and convert it into an int.

So that @"200hello" would become int = 200.

and @"0 something" would become int = 0.

Answer1(数字和字符排序不规则):

intvalue;

BOOL success=[[NSScannerscannerWithString:@"1000safkaj"]scanInteger:&value];

If the number is not always at the beginning:

NSCharacterSet* nonDigits = [[NSCharacterSet decimalDigitCharacterSet] invertedSet];

int value = [[@"adfsdg1000safkaj" stringByTrimmingCharactersInSet:nonDigits] intValue];

Answer2(数字总是在字符前):

If the int value is always at the beginning of the string, you can simply use intValue.

NSString*string=@"123hello";

int myInt = [string intValue];
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