求对称字符串的最大长度

//返回最长的对称字符串的长度，如google，对称字符串是goog，最大长度为4
int symStr(char* source)
{
if('\0' == *source)
return 0;
int maxLength = 1;
char* current = source;
while('\0' != *current)
{
int max1 = 0;
int symIndex = 0; // 对称游标
//(1) googllgox,对称字符个数为偶数,比如这样返回6,此时current + i + 1
while('\0' != *(current - symIndex - 1) && '\0' != *(current + symIndex) &&
*(current - symIndex - 1) == *(current + symIndex))
{
max1 += 2;
symIndex++;
}
maxLength = max(max1, maxLength);
max1 = 1;
symIndex = 1;
//(2)baidudiac,对称字符个数为奇数,比如这样返回7
while('\0' != *(current - symIndex) && '\0' != *(current + symIndex) &&
*(current - symIndex) == *(current + symIndex))
{
max1 += 2;
symIndex++;
}
maxLength = max(max1, maxLength);
++current;
}
return maxLength;
}