linux-0.11调试教程，update_line()函数分析，和update_line()函数的数据模型

如何由old变成new的？答案在最后！

例子一：

[/root]# c    -->    [/root]# ac       
按下a键， length为5

   

具体过程为：[/root]# c    -->    [/root]# a    -->    [/root]# ac

static

update_line (old, new, current_line)

     register char *old, *new;

     int current_line;

{     ....

          else

        {

          /* At the end of a line the characters do not have to

             be "inserted".  They can just be placed on the screen. */

          output_some_chars (nfd, lendiff);

          last_c_pos += lendiff;

        }

          /* Copy (new) chars to screen from first diff to last match. */

          if (((nls - nfd) - lendiff) > 0)

        {

          output_some_chars (&nfd[lendiff], ((nls - nfd) - lendiff));

          last_c_pos += ((nls - nfd) - lendiff);

        }

     ....

}

output_some_chars
(nfd, lendiff);时：



output_some_chars
(&nfd[lendiff], ((nls - nfd) - lendiff));时：



可见nfd为0x59c15,lendiff为1，nls为0x59c17,ne为0x59c17

(ofd为0x63415，ols和oe都为0x63416)

/* if (len (new) > len (old)) */

  lendiff = (nls - nfd) - (ols - ofd);          
   /* lendiff = 2-1=1 

例子2：下面的对应下面的图，退格键时的6个位置

  else                /* Delete characters from line. */

    {

      /* If possible and inexpensive to use terminal deletion, then do so. */

      if (term_dc && (2 * (ne - nfd)) >= (-lendiff))

    {

      if (lendiff)

        delete_chars (-lendiff); /* delete (diff) characters    
/*产生字符0x50315b1b*/

      /* Copy (new) chars to screen from first diff to last match   */

      if ((nls - nfd) > 0)

        {

          output_some_chars (nfd, (nls - nfd));  /*产生字符0x63*/

          last_c_pos += (nls - nfd);

        }

    }

[/root]# abc   -->      [/root]# ac  按下退格键，length为b



delete_chars (-lendiff);时



output_some_chars()时



lendiff = (nls - nfd) - (ols - ofd);

lendiff = 10 - 15 = -5;

先删除5个字符，delete_chars (-lendiff);/*产生字符0x50355b1b*/，会调用内核的csi_P()函数。

然后再打印出10个字符buggy say，把le-buggy i覆盖掉！！！

既调用output_some_chars (nfd, (nls - nfd));。



static void delete_char(int currcons)

{

    int i;

    unsigned short * p = (unsigned short *) pos;

    if (x>=video_num_columns)

        return;

    i = x;

    while (++i < video_num_columns) {

        *p = *(p+1);

        p++;

    }

    *p = video_erase_char;

}

static void csi_P(int currcons, unsigned int nr)

{

    if (nr > video_num_columns)

        nr = video_num_columns;

    else if (!nr)

        nr = 1;

    while (nr--)

        delete_char(currcons);

}