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西南石油大学第三届信息安全大赛之QR码

2012-11-03 19:50 375 查看
这几天在玩这个，发一下关于QR码的程序吧。

题目如下：



题目标题说明是QR码，看来是需要用程序来把上面的数字来生成QR码。代码如下：（基于OPENCV来实现的）

//由于图片太小，这里把图片放大了十倍



#include <stdio.h>
#include <stdlib.h>
#include "cv.h"
#include "cvaux.h"
#include "cxcore.h"
#include "highgui.h"

int main()
{
	int t[]={1,1,1,1,1,1,1,0,1,0,0,1,1,0,1,1,1,0,1,1,1,1,1,1,1,
1,0,0,0,0,0,1,0,0,1,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1,
1,0,1,1,1,0,1,0,0,0,1,0,1,0,0,1,1,0,1,0,1,1,1,0,1,
1,0,1,1,1,0,1,0,0,0,0,0,1,0,0,0,1,0,1,0,1,1,1,0,1,
1,0,1,1,1,0,1,0,0,1,0,1,0,0,1,0,0,0,1,0,1,1,1,0,1,
1,0,0,0,0,0,1,0,0,0,1,0,1,0,0,0,0,0,1,0,0,0,0,0,1,
1,1,1,1,1,1,1,0,1,0,1,0,1,0,1,0,1,0,1,1,1,1,1,1,1,
0,0,0,0,0,0,0,0,1,0,1,1,0,1,0,1,1,0,0,0,0,0,0,0,0,
1,1,0,1,1,0,1,0,0,1,1,1,0,1,0,0,0,0,1,0,0,0,0,0,1,
1,0,0,0,0,0,0,0,1,1,0,0,1,1,0,0,0,1,0,1,1,1,0,1,1,
0,1,1,1,1,0,1,0,0,0,1,1,0,1,0,1,0,1,1,1,1,0,1,0,1,
0,1,1,1,1,1,0,0,1,1,1,1,1,1,0,0,0,0,0,0,0,1,1,1,0,
1,0,0,0,0,1,1,0,0,1,0,1,1,1,0,0,1,0,1,0,0,1,0,1,1,
1,0,1,1,0,1,0,0,1,1,0,0,0,1,1,1,1,1,1,1,1,0,0,1,0,
1,1,1,0,1,1,1,1,0,0,0,1,1,1,0,1,0,1,0,0,1,0,0,1,1,
1,0,1,1,0,0,0,1,0,0,0,1,0,0,0,1,0,1,0,1,0,0,1,1,1,
1,0,1,0,1,0,1,0,1,1,0,0,0,0,1,0,1,1,1,1,1,0,1,1,1,
0,0,0,0,0,0,0,0,1,0,0,1,1,1,1,0,1,0,0,0,1,0,1,0,1,
1,1,1,1,1,1,1,0,0,0,1,1,0,0,0,0,1,0,1,0,1,1,1,0,1,
1,0,0,0,0,0,1,0,0,1,0,0,1,0,1,1,1,0,0,0,1,1,0,1,1,
1,0,1,1,1,0,1,0,1,0,0,0,1,1,1,1,1,1,1,1,1,1,0,0,1,
1,0,1,1,1,0,1,0,1,0,1,0,0,0,1,0,1,1,1,1,1,1,1,1,1,
1,0,1,1,1,0,1,0,0,0,1,0,1,0,1,1,0,1,0,1,1,1,0,1,1,
1,0,0,0,0,0,1,0,1,0,1,0,0,0,1,1,0,1,1,1,0,1,1,1,1,
1,1,1,1,1,1,1,0,1,0,0,0,0,1,1,1,1,0,0,0,1,1,0,0,1};
	cvNamedWindow("a");
	IplImage* img=cvCreateImage(cvSize(250,250),IPL_DEPTH_8U,1);
	int m,n;
	for(int i=0;i<250;++i)       
	{
		for(int j=0;j<250;++j)
		{
			m=i/10;
			n=j/10;
			if(t[n*25+m]==0)
				((uchar*)(img->imageData+img->widthStep*j))[i]=(char)(255);
			else
				((uchar*)(img->imageData+img->widthStep*j))[i]=(char)(0);
		}
	}
	cvShowImage("a",img);
	cvWaitKey(0);
	//system("pause");
	return 0;
}
效果如下：



百度上传扫一下就出来了。
                                            

                                        

                        
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