URLRewrite实现伪静态 url重写
2012-09-23 15:01
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是否看到别人的网站网址名都不带后缀名比较酷,比如qq空间的地址,其实用urlrewrite这个包很容易就实现了。
下面是使用说明:
1.下载urlrewrite,官方下载地址:http://tuckey.org/urlrewrite/dist/urlrewritefilter-2.6.zip
2.解压缩文件,压缩包内文件copy到项目中(压缩包位置 -> 项目位置):
urlrewrite-2.6.0-src/webapp/WEB-INF/lib/urlrewrite-2.6.0.jar -> WebRoot/WEB-INF/lib/urlrewrite-2.6.0.jar
urlrewrite-2.6.0-src/webapp/WEB-INF/urlrewrite.xml -> WebRoot/WEB-INF/urlrewrite.xml
3.将以下代码添加到web.xml里
<filter>
<filter-name>UrlRewriteFilter</filter-name>
<filter-class>
org.tuckey.web.filters.urlrewrite.UrlRewriteFilter
</filter-class>
</filter>
<filter-mapping>
<filter-name>UrlRewriteFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
4.修改urlrewrite.xml
<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE urlrewrite PUBLIC "-//tuckey.org//DTD UrlRewrite 2.6//EN"
"http://tuckey.org/res/dtds/urlrewrite2.6.dtd">
<!--
Configuration file for UrlRewriteFilter
http://tuckey.org/urlrewrite/
-->
<urlrewrite>
<rule>
<from>^/([a-z]+)$</from>
<to type= "forward" >/world.jsp?id=$1</to>
</rule>
<rule>
<from>^/world/(.*)$</from>
<to>/world.jsp?tid=$1</to>
</rule>
<rule>
<from>^/(.*).html$</from>
<to>/test1/$1.jsp</to>
</rule>
<outbound-rule>
<note>
The outbound-rule specifies that when response.encodeURL is called (if you are using JSTL c:url)
the url /rewrite-status will be rewritten to /test/status/.
The above rule and this outbound-rule means that end users should never see the
url /rewrite-status only /test/status/ both in thier location bar and in hyperlinks
in your pages.
</note>
<from>/rewrite-status</from>
<to>/test/status/</to>
</outbound-rule>
</urlrewrite>
rule是url重写规则,from是显示出来的地址,to是映射的实际地址,$1是重写参数,可以为多个,()里是匹配的正则表达式.
好了,在项目中新建world.jsp,启动tomcat,输入
http://localhost:8080/mysite/world/1
mysite是你的项目名
实际上访问的是http://localhost:8080/mysite/world.jsp?tid=1
这样就简单的实现了伪静态的效果
下面是使用说明:
1.下载urlrewrite,官方下载地址:http://tuckey.org/urlrewrite/dist/urlrewritefilter-2.6.zip
2.解压缩文件,压缩包内文件copy到项目中(压缩包位置 -> 项目位置):
urlrewrite-2.6.0-src/webapp/WEB-INF/lib/urlrewrite-2.6.0.jar -> WebRoot/WEB-INF/lib/urlrewrite-2.6.0.jar
urlrewrite-2.6.0-src/webapp/WEB-INF/urlrewrite.xml -> WebRoot/WEB-INF/urlrewrite.xml
3.将以下代码添加到web.xml里
<filter>
<filter-name>UrlRewriteFilter</filter-name>
<filter-class>
org.tuckey.web.filters.urlrewrite.UrlRewriteFilter
</filter-class>
</filter>
<filter-mapping>
<filter-name>UrlRewriteFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
4.修改urlrewrite.xml
<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE urlrewrite PUBLIC "-//tuckey.org//DTD UrlRewrite 2.6//EN"
"http://tuckey.org/res/dtds/urlrewrite2.6.dtd">
<!--
Configuration file for UrlRewriteFilter
http://tuckey.org/urlrewrite/
-->
<urlrewrite>
<rule>
<from>^/([a-z]+)$</from>
<to type= "forward" >/world.jsp?id=$1</to>
</rule>
<rule>
<from>^/world/(.*)$</from>
<to>/world.jsp?tid=$1</to>
</rule>
<rule>
<from>^/(.*).html$</from>
<to>/test1/$1.jsp</to>
</rule>
<outbound-rule>
<note>
The outbound-rule specifies that when response.encodeURL is called (if you are using JSTL c:url)
the url /rewrite-status will be rewritten to /test/status/.
The above rule and this outbound-rule means that end users should never see the
url /rewrite-status only /test/status/ both in thier location bar and in hyperlinks
in your pages.
</note>
<from>/rewrite-status</from>
<to>/test/status/</to>
</outbound-rule>
</urlrewrite>
rule是url重写规则,from是显示出来的地址,to是映射的实际地址,$1是重写参数,可以为多个,()里是匹配的正则表达式.
好了,在项目中新建world.jsp,启动tomcat,输入
http://localhost:8080/mysite/world/1
mysite是你的项目名
实际上访问的是http://localhost:8080/mysite/world.jsp?tid=1
这样就简单的实现了伪静态的效果
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