有一个整数数组，请求出两两之差绝对值的最小值

#include<iostream>
#include<algorithm>
#define MAX  1000
using namespace std;
int a[] = {-3,4,2,7,25,0,8,-2};
int getMin(int a[],int i,int j)
{
return abs(a[i]-a[j]);
}
int main()
{
int len = sizeof(a)/sizeof(int);
int min = MAX;
for(int i=0;i<len-1;i++)
{
for(int j=i+1;j<len;j++)
{
int num = getMin(a,i,j);
min = min>num?num:min;
}
}
cout<<"min: "<<min<<endl;
getchar();
return 0;
}

#include<iostream>
#include<algorithm>
using namespace std;
int a[] = {-3,4,2,7,25,0,8,-2};
int main()
{
int len =sizeof(a)/sizeof(int);
sort(a,a+len);//调用sort(b,e)方法
int min =50;
for(int i=len-1; i>0;i--)
{
min = (abs(a[i]-a[i-1])>min)?min:abs(a[i]-a[i-1]);
}
cout<<"min "<<min<<endl;
getchar();
return 0;
}