python 根据监控结果发送邮件

使用gg后，需要监控，自己写个自动发送邮件，这只是个原型！根据从数据库返回的数据结果是1还是2来判断同步情况，

并及时发送邮件并短信通知以及记录日志！

# -*- coding: gb2312 -*-

import re

import pyodbc

import traceback

import decimal

import os, sys

import time

import smtplib

from email.mime.text import MIMEText

from email.header import Header

sender = '1364188****@139.com'

receiver = '1364188****@139.com'

subject = '数据同步监控'

smtpserver = 'smtp.139.com'

username = '1364188****'

password = '************'

########判断同步是否正常

guess = int(input("请输入一个整数:\n"))

if guess == 1:

msg = MIMEText('监控正常!','plain','gb2312')#中文需参数‘gb2312’，单字节字符不需要

msg['Subject'] = Header(subject, 'gb2312')

msg['date']=time.strftime('%Y-%m-%d %H:%M:%S', time.localtime())

smtp = smtplib.SMTP()

smtp.connect('smtp.139.com')

smtp.login(username, password)

smtp.sendmail(sender, receiver, msg.as_string())

logtxt='监控邮件已经在'+msg['date']+'发送成功!'+':同步正常'

smtp.quit()

print (logtxt)

f = open('e:\py\log.txt', 'a')

f.write(logtxt+'\n')

f.close()

print ( '日志:'+logtxt+'记录成功' )

elif guess == 2:

msg = MIMEText('监控异常!','plain','gb2312')#中文需参数‘gb2312’，单字节字符不需要

msg['Subject'] = Header(subject, 'gb2312')

msg['date']=time.strftime('%Y-%m-%d %H:%M:%S', time.localtime())

smtp = smtplib.SMTP()

smtp.connect('smtp.139.com')

smtp.login(username, password)

smtp.sendmail(sender, receiver, msg.as_string())

logtxt='监控邮件已经在'+msg['date']+'发送成功!'+':同步异常'

smtp.quit()

print (logtxt)

f = open('e:\py\log.txt', 'a')

f.write(logtxt+'\n')

f.close()

print ( '日志:'+logtxt+'记录成功' )

else:

print ('**************输入类型不对，请联系ocpyang!**********************')
http://blog.csdn.net/yangzhawen/article/details/7858877