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chrome ajaxSubmit form提交乱码

2012-07-20 10:56 253 查看
jsp页面进行转码

$("#parasummary").attr("value",escape($("#summary").val()));

form提交到java后用下面的函数解码就可以了

/**

* 汉字解码

* @param urlStr

* @return

* @author:Wangjc

*/

public static String unescape(String src) {

StringBuffer tmp = new StringBuffer();

tmp.ensureCapacity(src.length());

int lastPos = 0, pos = 0;

char ch;

while (lastPos < src.length()) {

pos = src.indexOf("%", lastPos);

if (pos == lastPos) {

if (src.charAt(pos + 1) == 'u') {

ch = (char) Integer.parseInt(src

.substring(pos + 2, pos + 6), 16);

tmp.append(ch);

lastPos = pos + 6;

} else {

ch = (char) Integer.parseInt(src

.substring(pos + 1, pos + 3), 16);

tmp.append(ch);

lastPos = pos + 3;

}

} else {

if (pos == -1) {

tmp.append(src.substring(lastPos));

lastPos = src.length();

} else {

tmp.append(src.substring(lastPos, pos));

lastPos = pos;

}

}

}

return tmp.toString();

}

还有一个函数是java的转码函数,如下

/**

* 汉字编码

* @param urlStr

* @return

* @author:Wangjc

*/

public static String escape(String src) {

int i;

char j;

StringBuffer tmp = new StringBuffer();

tmp.ensureCapacity(src.length() * 6);

for (i = 0; i < src.length(); i++) {

j = src.charAt(i);

if (Character.isDigit(j) || Character.isLowerCase(j)

|| Character.isUpperCase(j))

tmp.append(j);

else if (j < 256) {

tmp.append("%");

if (j < 16)

tmp.append("0");

tmp.append(Integer.toString(j, 16));

} else {

tmp.append("%u");

tmp.append(Integer.toString(j, 16));

}

}

return tmp.toString();

}
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