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怎样在Android中解析doc、docx、xls、xlsx格式文件？

2012-07-17 17:32 525 查看
可以直接复制实验，

解析doc，要tm-extractors-0.4.jar这个包

解析xls，要jxl.jar这个包

01
public
static
String
readDOC(String path) {
02
//
创建输入流读取doc文件
03
FileInputStream
in;
04
String
text =
null
;
05
//
Environment.getExternalStorageDirectory().getAbsolutePath()+ "/aa.doc")
06
try
 
{
07
in
=
new
 
FileInputStream(
new
 
File(path));
08
int
 
a=
in.available();
09
WordExtractor
extractor =
null
;
10
//
创建WordExtractor
11
extractor
=
new
 
WordExtractor();
12
//
对doc文件进行提取
13
text
= extractor.extractText(in);
14
System.out.println(
"解析得到的东西"
+text);
15
}
catch
 
(FileNotFoundException
e) {
16
e.printStackTrace();
17
}
catch
 
(Exception
e) {
18
e.printStackTrace();
19
}
20
if
 
(text
==
null
)
{
21
text
=
"解析文件出现问题"
;
22
}
23
return
 
text;
24
}
解析xls

view
source

print?

01
public
 
static
 
String
readXLS(String path) {
02
String
str =
""
;
03
try
 
{
04
Workbook
workbook =
null
;
05
workbook
= Workbook.getWorkbook(
new
 
File(path));
06
Sheet
sheet = workbook.getSheet(
0
);
07
Cell
cell =
null
;
08
int
 
columnCount
= sheet.getColumns();
09
int
 
rowCount
= sheet.getRows();
10
for
 
(
int
 
i
=
0
;
i < rowCount; i++) {
11
for
 
(
int
 
j
=
0
;
j < columnCount; j++) {
12
cell
= sheet.getCell(j,i);
13
String
temp2 =
""
;
14
if
 
(cell.getType()
== CellType.NUMBER) {
15
temp2
= ((NumberCell) cell).getValue() +
""
;
16
}
else
 
if
 
(cell.getType()
== CellType.DATE) {
17
temp2
=
""
 
+
((DateCell) cell).getDate();
18
}
else
 
{
19
temp2
=
""
 
+
cell.getContents();
20
}
21
str
= str +
"
"
 
+
temp2;
22
}
23
str
+=
"\n"
;
24
}
25
workbook.close();
26
}
catch
 
(Exception
e) {
27
}
28
if
 
(str
==
null
)
{
29
str
=
"解析文件出现问题"
;
30
}
31
return
 
str;
32
}
解析docx

public
 
static
 
String
readDOCX(String path) {
02
String
river =
""
;
03
try
 
{
04
ZipFile
xlsxFile =
new
 
ZipFile(
new
 
File(path));
05
ZipEntry
sharedStringXML = xlsxFile.getEntry(
"word/document.xml"
);
06
InputStream
inputStream = xlsxFile.getInputStream(sharedStringXML);
07
XmlPullParser
xmlParser = Xml.newPullParser();
08
xmlParser.setInput(inputStream,
"utf-8"
);
09
int
 
evtType
= xmlParser.getEventType();
10
while
 
(evtType
!= XmlPullParser.END_DOCUMENT) {
11
switch
 
(evtType)
{
12
case
 
XmlPullParser.START_TAG:
13
String
tag = xmlParser.getName();
14
System.out.println(tag);
15
if
 
(tag.equalsIgnoreCase(
"t"
))
{
16
river
+= xmlParser.nextText() +
"\n"
;
17
}
18
break
;
19
case
 
XmlPullParser.END_TAG:
20
break
;
21
default
:
22
break
;
23
}
24
evtType
= xmlParser.next();
25
}
26
}
catch
 
(ZipException
e) {
27
e.printStackTrace();
28
}
catch
 
(IOException
e) {
29
e.printStackTrace();
30
}
catch
 
(XmlPullParserException
e) {
31
e.printStackTrace();
32
}
33
if
 
(river
==
null
)
{
34
river
=
"解析文件出现问题"
;
35
}
36
return
 
river;
37
}
解析xlsx

view
source

print?

01
public
 
static
 
String
readXLSX(String path) {
02
String
str =
""
;
03
String
v =
null
;
04
boolean
 
flat
=
false
;
05
List<String>
ls =
new
 
ArrayList<String>();
06
try
 
{
07
ZipFile
xlsxFile =
new
 
ZipFile(
new
 
File(path));
08
ZipEntry
sharedStringXML = xlsxFile
09
.getEntry(
"xl/sharedStrings.xml"
);
10
InputStream
inputStream = xlsxFile.getInputStream(sharedStringXML);
11
XmlPullParser
xmlParser = Xml.newPullParser();
12
xmlParser.setInput(inputStream,
"utf-8"
);
13
int
 
evtType
= xmlParser.getEventType();
14
while
 
(evtType
!= XmlPullParser.END_DOCUMENT) {
15
switch
 
(evtType)
{
16
case
 
XmlPullParser.START_TAG:
17
String
tag = xmlParser.getName();
18
if
 
(tag.equalsIgnoreCase(
"t"
))
{
19
ls.add(xmlParser.nextText());
20
}
21
break
;
22
case
 
XmlPullParser.END_TAG:
23
break
;
24
default
:
25
break
;
26
}
27
evtType
= xmlParser.next();
28
}
29
ZipEntry
sheetXML = xlsxFile.getEntry(
"xl/worksheets/sheet1.xml"
);
30
InputStream
inputStreamsheet = xlsxFile.getInputStream(sheetXML);
31
XmlPullParser
xmlParsersheet = Xml.newPullParser();
32
xmlParsersheet.setInput(inputStreamsheet,
"utf-8"
);
33
int
 
evtTypesheet
= xmlParsersheet.getEventType();
34
while
 
(evtTypesheet
!= XmlPullParser.END_DOCUMENT) {
35
switch
 
(evtTypesheet)
{
36
case
 
XmlPullParser.START_TAG:
37
String
tag = xmlParsersheet.getName();
38
if
 
(tag.equalsIgnoreCase(
"row"
))
{
39
}
else
 
if
(tag.equalsIgnoreCase(
"c"
))
{
40
String
t = xmlParsersheet.getAttributeValue(
null
,
"t"
);
41
if
 
(t
!=
null
)
{
42
flat
=
true
;
43
System.out.println(flat
+
"有"
);
44
}
else
 
{
45
System.out.println(flat
+
"没有"
);
46
flat
=
false
;
47
}
48
}
else
 
if
(tag.equalsIgnoreCase(
"v"
))
{
49
v
= xmlParsersheet.nextText();
50
if
 
(v
!=
null
)
{
51
if
 
(flat)
{
52
str
+=ls.get(Integer.parseInt(v)) + 
"
"
;
53
}
else
 
{
54
str
+=v + 
"
"
;
55
}
56
}
57
}
58
break
;
59
case
 
XmlPullParser.END_TAG:
60
if
(xmlParsersheet.getName().equalsIgnoreCase(
"row"
)
61
&&
v !=
null
)
{
62
str
+=
"\n"
;
63
}
64
break
;
65
}
66
evtTypesheet
= xmlParsersheet.next();
67
}
68
System.out.println(str);
69
}
catch
 
(ZipException
e) {
70
e.printStackTrace();
71
}
catch
 
(IOException
e) {
72
e.printStackTrace();
73
}
catch
 
(XmlPullParserException
e) {
74
e.printStackTrace();
75
}
76
if
 
(str
==
null
)
{
77
str
=
"解析文件出现问题"
;
78
}
79
return
 
str;
80
}

                                            

                                        

                        
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                         标签： 
                                                android
                                                string
                                                null
                                                path
                                                exception
                                                n2
                                                

                        

                    


                

            


            

                
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