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ExtAsp.Net中弹出新窗口并得到返回值(TriggerBox控件)

2012-04-05 09:21 483 查看
刚进这行不久,什么还不会,这是我的第一篇文章,很简单但折腾了我半天的问题。

我想在水电录入form页面中通过按钮选择所有房间。主要通过TriggerBox控件的实现。

form 页面前台代码:

<ext:FormRow ID="FormRow1" runat="server" >

<Items>

<ext:TriggerBox ID="a" runat="server" Label="房间名称" TriggerIcon="Search">

</ext:TriggerBox>

<ext:HiddenField ID="hdfSjr" runat="server"> </ext:HiddenField>

</Items>

</ext:FormRow>

<ext:Window ID="Window2" Title="选择房间" Popup="false" EnableIFrame="true" runat="server"

Target="Self" IsModal="True" Width="400px" Height="300px" >

</ext:Window>



Form页面后台代码

this.a.OnClientTriggerClick = Window2.GetSaveStateReference(a.ClientID, hdfSjr.ClientID) + Window2.GetShowReference("/2052/Aspx/Wygl/PowerWaterRoomList.aspx");

跳转房间list界面的前台代码

<ext:ToolbarSeparator ID="ToolbarSeparator2" runat="server">

</ext:ToolbarSeparator>

<ext:Button ID="btnConfirm" Text=" 确认 " Icon="ApplicationFormDelete" runat="server" OnClick="btnConfirm_Click">

</ext:Button>

<Items>

<ext:Grid ID="Grid2" Title="Grid2" PageSize="50" ShowBorder="false" ShowHeader="false" EnableRowNumber="True" AllowPaging="true"

AutoWidth="true" runat="server" EnableCheckBoxSelect="True" OnPageIndexChange="Grid2_PageIndexChange"

DataKeyNames="oid,RoomNumber">

<Columns>

<ext:BoundField Width="100px" DataField="RoomNumber" HeaderText="办公楼房间" />

</Columns>

</ext:Grid>

</Items>

(注意这里的DataKeyNames=就是你要想返回的值,一个是oid必须的。。。)



跳转房间list界面的后台代码

protected void btnConfirm_Click(object sender, EventArgs e)

{

string clientName = "";

string clientOid = "";

int[] arr = this.Grid2.SelectedRowIndexArray;

if (arr.Length > 1)

{

ExtAspNet.Alert.ShowInTop("只能选中一条!");

}

else if (arr.Length < 1)

{

ExtAspNet.Alert.ShowInTop("必须选中一条!");

}

else

{

clientOid = this.Grid2.Rows[arr[0]].DataKeys[0].ToString();

clientName = this.Grid2.Rows[arr[0]].DataKeys[1].ToString();

PageContext.RegisterStartupScript(ActiveWindow.GetWriteBackValueReference(clientName, clientOid) + ActiveWindow.GetHideReference());

}

}
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