USACO 1.2.3 Name That Number
2012-02-21 21:52
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思路:先把dict.txt中的名字都转化成数字,存储在数组中,便于查找。需要注意的是数字与字母的对应表里没有字母Q和Z,还有就是如果有多组满足题意,则都需要输出。
代码如下:
代码如下:
/* ID: michael139 LANG: C PROG: namenum */ #include<stdio.h> #include<string.h> char table[8][4]={"ABC","DEF","GHI","JKL","MNO","PRS","TUV","WXY"}; char word[5050][15],word_num[5050][15]; int main () { FILE *fin = fopen("namenum.in", "r"); FILE *fout = fopen("namenum.out", "w"); FILE *fin2 = fopen("dict.txt","r"); char num[15],temp[15]; int len,i,j,m,k = 0,ok; while (fscanf(fin2,"%s",temp) != EOF) { len = strlen(temp); for (i=0;i<len;i++) { ok = 0; for (j=0;j<8;j++) { for (m=0;m<3;m++) { if (temp[i]==table[j][m]) { word_num[k][i] = j+2+'0'; ok = 1; break; } } if (ok) break; } if (!ok) word_num[k][i] = 'X'; } strcpy(word[k],temp); k ++; } while (fscanf(fin,"%s",num) != EOF) { ok = 0; for (i=0;i<k;i++) { if (!strcmp(num,word_num[i])) { fprintf(fout,"%s\n",word[i]); ok = 1; } } if (!ok) fprintf(fout,"NONE\n"); } return 0; }
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