处理回车事件是否有既兼容ie又兼容火狐的方法

document.onkeypress = function (e) {

var code;

if (!e) {

var e = window.event;

}

if (e.keyCode) {

code = e.keyCode;

}

else if (e.which) {

code = e.which;

}

if (code == 13) {

document.getElementById("searchButton").click();

return false;

}

}