android 应用程序实现开机自启动

import android.content.BroadcastReceiver;
import android.content.Context;
import android.content.Intent;
import android.util.Log;

public class BootReceiver extends BroadcastReceiver {
        static final String ACTION = "android.intent.action.BOOT_COMPLETED";
        @Override
        public void onReceive(Context context, Intent intent) {
                // TODO Auto-generated method stub
                Log.d("BootReceiver", "system boot completed");  
            //start activity  
                if (intent.getAction().equals(ACTION)){
                     Intent myi=new Intent(context,MainActivity.class); 
                     myi.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);  
                     context.startActivity(myi);  
      }
        }
}
    然后在AndroidManifest.xml   MainActivity中添加  
      <intent-filter>
                <action android:name="android.intent.action.MAIN" />
                <category android:name="android.intent.category.LAUNCHER" />
                <category android:name="android.intent.category.HOME" />
                <category android:name="android.intent.category.DEFAULT" />  
                <category android:name="android.intent.category.MONKEY" />
            </intent-filter>

还需要把BootReceiver在AndroidManifest.xml   中注册
   <receiver android:name=".BootReceiver"> 
       <intent-filter> 
        <action android:name="android.intent.action.BOOT_COMPLETED"/> 
        <category android:name="android.intent.category.HOME" /> 
   </intent-filter> 
   </receiver>
            然后就可以实现自启动了啊！