字符串分割成一维数组、二维数组，一维数组与二维数组之间的转换

指定格式的字符串截成一维数组(二维数组)的操作类
做项目时经常会遇到将"1,3,a,b,d"截成一维数组或将"1,a;2,b;3,c;4,d"截成二维数组。虽然String.Split()可以实现，但我感觉在遍历取值时还不是很方便。

所以写下clsArrayList类,专门做这方面的处理。

注：myClass.clsLogHelper 为写错误日志类，在我的博客中有写，有兴趣的朋友可能看一下。

using System;
using System.Text;

namespace myClass
{
class clsArrayList
{
public int p_Count=-1; //数据组数
private string[] myArray1; //一维矩阵
private string[,] myArray2; //二维矩阵

/// <summary>
/// 一维字符串分隔,初始化.例: clsArrayList myArray1List=new clsArrayList("1;2;3;4;5",';')
/// </summary>
/// <param name="strStringSource"></param>
/// <remarks>gx 2010-04-25</remarks>
public clsArrayList(string strStringSource, char charSepartor)
{
try
{
myArray1 = strStringSource.Split(charSepartor);//截取
p_Count = myArray1.Length;
}
catch(Exception ex)
{
myClass.clsLogHelper.m_CreateErrorLogTxt("clsArrayList(" + strStringSource + " , " + charSepartor + ")", "", ex.Message.ToString());
}
}

/// <summary>
/// 二维字符串分隔,初始化. 例: clsArrayList myArray1List=new clsArrayList("1,A;2,B;3,C;4,D;5,E" , ';' , ',')
/// </summary>
/// <param name="strStringSource"></param>
/// <param name="strColumnSepartor"></param>
/// <param name="strRowSepartor"></param>
/// <remarks>gx 2010-04-25</remarks>
public clsArrayList(string strStringSource, char charColumnSepartor, char charRowSepartor)
{
try
{
string[] strColumn; //第一次截取  ";"
string[] strRow; //第二次截取  ","

strColumn = strStringSource.Split(charColumnSepartor);//第一次截取
p_Count = strColumn.Length;

myArray2 = new string[p_Count, 2];
for (int i = 0; i <= p_Count - 1; i++) //将数据保存 数组 myArray1 中
{
strRow = strColumn[i].Split(charRowSepartor);//第二次截取
myArray2[i, 0] = strRow[0];
myArray2[i, 1] = strRow[1];
}
}
catch (Exception ex)
{
myClass.clsLogHelper.m_CreateErrorLogTxt("clsArrayList(" + strStringSource + " , " + charColumnSepartor + " , " + charRowSepartor + ")", "", ex.Message.ToString());
}
}

/// <summary>
/// 一维字符串,取值
/// </summary>
/// <param name="intIndex"></param>
/// <returns></returns>
public string m_GetItem(int intIndex)
{
if (myArray1 == null)
{
return "";
}
if (p_Count == - 1)
{
return "";
}
if (intIndex > p_Count - 1)
{
return "";
}
else
{
return myArray1[intIndex];
}
}

/// <summary>
/// 二维字符串,取值
/// </summary>
/// <param name="intKeyIndex"></param>
/// <param name="intValueIndex"></param>
/// <returns></returns>
/// <remarks>gx 2010-04-25</remarks>
public string m_GetItem(int intKeyIndex,int intValueIndex)
{
if (myArray2 == null)
{
return "";
}
if (p_Count == -1)
{
return "";
}
if (intKeyIndex > p_Count - 1 || intValueIndex > 1)//Value为列,二维
{
return "";
}
else
{
return myArray2[intKeyIndex, intValueIndex];
}
}

/// <summary>
/// 二维字符串,通过Value 获取Key ,例: m_GetKey("1")
/// </summary>
/// <param name="strValue"></param>
/// <returns></returns>
/// <remarks>gx 2010-04-25</remarks>
public string m_GetKey(string strValue)
{
try
{
if (myArray2 == null)
{
return "";
}
if (p_Count == -1)
{
return "";
}
for (int i = 0; i <= p_Count - 1; i++) //通过value查找key
{
if (myArray2[i, 1] == strValue)
{
return myArray2[i, 0]; //返回key的值
}
}
return "";
}
catch(Exception ex)
{
myClass.clsLogHelper.m_CreateErrorLogTxt("clsArrayList(" + strValue + ")", "", ex.Message.ToString());
return "";
}

}

/// <summary>
/// 二维字符串,通过Key 获取Value
/// </summary>
/// <param name="strKey"></param>
/// <returns></returns>
/// <remarks>gx 2010-04-25</remarks>
public string m_GetValue(string strKey)
{
try
{
if (myArray2 == null)
{
return "";
}
if (p_Count == -1)
{
return "";
}
for (int i = 0; i <= p_Count - 1; i++) //通过key查找value
{
if (myArray2[i, 0] == strKey)
{
return myArray2[i, 1]; //返回value的值
}
}
return "";

}
catch(Exception ex)
{
myClass.clsLogHelper.m_CreateErrorLogTxt("m_GetValue(" + strKey + ")", "", ex.Message.ToString());
return "";

一维数组和二维数组的转换表示(C#)

关键:下标的计算

一维->二维

一个n个元素的一维数组，转换为r行c列的二维数组

对于一维数组中任意一个元素的下标i(0 <= i < n)

其对应的二维数组下标为 (i / c, i % c), 显然, 只与列数c有关，而与行数r无关

code like this

int[] a = new int
;
int[,] b = new int[r, c];

for (int i = 0; i < n; i++)
b[i / c, i % c] = a[i];

also can write like this

for (int i = 0; i < r; i++)
{
for (int j = 0; j < c; j++)
{
b[i, j] = a[i * c + j];
}
}

二维->一维

int[,] a = new int[r, c];
int[] b = new int[r * c];
for(int i = 0; i < b.Length; i++)
b[i] = a[i / c, i % c];