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将身份证的位号码升级为位

2010-10-29 13:10 225 查看
-- --下面定义好的调用函数
-- update
-- 表
-- set
-- 身份证号= dbo.ID15TO18(身份证号)
-- where

-- LEN(身份证号) = 15

dbo.ID15TO18函数

Create FUNCTION [dbo].[ID15TO18] (@id15 char(15))
RETURNS CHAR(18)
AS
BEGIN
DECLARE @ID18 CHAR(18)
DECLARE @S1 AS INTEGER
DECLARE @S2 AS INTEGER
DECLARE @S3 AS INTEGER
DECLARE @S4 AS INTEGER
DECLARE @S5 AS INTEGER
DECLARE @S6 AS INTEGER
DECLARE @S7 AS INTEGER
DECLARE @S8 AS INTEGER
DECLARE @S9 AS INTEGER
DECLARE @S10 AS INTEGER
DECLARE @S11 AS INTEGER
DECLARE @S12 AS INTEGER
DECLARE @S13 AS INTEGER
DECLARE @S14 AS INTEGER
DECLARE @S15 AS INTEGER
DECLARE @S16 AS INTEGER
DECLARE @S17 AS INTEGER
DECLARE @S18 AS INTEGER
SET @S1=SUBSTRING(@ID15,1,1)
SET @S2=SUBSTRING(@ID15,2,1)
SET @S3=SUBSTRING(@ID15,3,1)
SET @S4=SUBSTRING(@ID15,4,1)
SET @S5=SUBSTRING(@ID15,5,1)
SET @S6=SUBSTRING(@ID15,6,1)
SET @S7=1
SET @S8=9
SET @S9=SUBSTRING(@ID15,7,1)
SET @S10=SUBSTRING(@ID15,8,1)
SET @S11=SUBSTRING(@ID15,9,1)
SET @S12=SUBSTRING(@ID15,10,1)
SET @S13=SUBSTRING(@ID15,11,1)
SET @S14=SUBSTRING(@ID15,12,1)
SET @S15=SUBSTRING(@ID15,13,1)
SET @S16=SUBSTRING(@ID15,14,1)
SET @S17=SUBSTRING(@ID15,15,1)

SET @S18=((@S1*7) (@S2*9) (@S3*10) (@S4*5) (@S5*8) (@S6*4) (@S7*2) (@S8*1)
(@S9*6) (@S10*3) (@S11*7) (@S12*9) (@S13*10) (@S14*5) (@S15*8) (@S16
*4) (@S17*2))
SET @ID18=SUBSTRING(@ID15,1,6) '19' SUBSTRING(@ID15,7,9)
CASE WHEN @S18=0 THEN '1'
WHEN @S18=1 THEN '0'
WHEN @S18=2 THEN 'X'
WHEN @S18=3 THEN '9'
WHEN @S18=4 THEN '8'
WHEN @S18=5 THEN '7'
WHEN @S18=6 THEN '6'
WHEN @S18=7 THEN '5'
WHEN @S18=8 THEN '4'
WHEN @S18=9 THEN '3'
WHEN @S18=10 THEN '2'
END
RETURN @ID18
END
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