Android java.lang.IllegalArgumentException: parameter must be a descendant of this view
2010-09-10 14:24
681 查看
所有view必须嵌套在同一个父级布局中,在通过findViewById方法获得view对象时,所有view的引用必须统一,比如都是用this来引用;
相关文章推荐
- 错误 java.lang.IllegalArgumentException: parameter must be a descendant of this view 的解决方案
- java.lang.IllegalArgumentException: parameter must be a descendant of this view
- java.lang.IllegalArgumentException parameter must be a descendant of this view
- java.lang.IllegalArgumentException: parameter must be a descendant of this view
- 错误 java.lang.IllegalArgumentException: parameter must be a descendant of this view 的解决方案
- java.lang.IllegalArgumentException: parameter must be a descendant of this view
- [Android] View.setTag(key,Object) (java.lang.IllegalArgumentException: The key must be an application-specific resource id.)
- java.lang.IllegalArgumentException: AppIndex: The URI scheme must be 'android-app' and follow the fo
- android-奇异bug:parameter must be a descendant of this view
- Android解决"parameter must be a descendant of this view(参数必须是此视图的子视图 )"问题的方法
- Android java.lang.IllegalArgumentException: Object returned from onCreateLoader must not be a non-static inn
- Android报错:Caused by: java.lang.IllegalArgumentException: Service Intent must be explicit: Intent
- android L java.lang.IllegalArgumentException: Service Intent must be explicit隐式意图找不到错误解决
- java.lang.IllegalArgumentException: At least one handler method must be found in class [class SayThr
- java.lang.IllegalArgumentException: Service Intent must be explicit异常说明
- ViewPager中的图片多点触摸出现java.lang.IllegalArgumentException: pointerIndex out of range解决方案
- 【原创】【ViewFlow+GridView】Parameter must be a descendant of this view问题分析
- java.lang.IllegalArgumentException: Service Intent must be explicit
- java.lang.IllegalArgumentException: SessionContext must be an HTTP compatible implementation.:模块化本地测试shiro的一些总结
- android ICS 4.0.3 报 java.lang.IllegalArgumentException: pointerIndex out of range 解决方案