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《汇编语言(王爽)》(第八章、实验7寻址方式在结构化数据访问中的应用)学习笔记

2010-07-08 11:15 573 查看
注意对结果"divide overflow"的调试:被除数为16位时,除数高位移到dx中,低位移到ax中(注意在内存中数据的排列方式,先低位:

mov ax,[bx];在高位:mov dx,[bx+2];)

调试过程中要仔细,不能浮躁

assume cs:codesg,ds:datasg,ss:stacksg
datasg segment
db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
db '1993','1994','1995'
dd 16,22,382,1356,2390,8000,16000,24486,50065,97497,140417,197514
dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 11542,14430,15257,17800
datasg ends
table segment
db 21 dup ('yaar sumn ne ?? ')
table ends
stacksg segment
dw 0,0,0,0,0,0,0,0
stacksg ends
codesg segment
start:
mov ax,datasg
mov ds,ax
mov ax,table
mov es,ax
mov ax,stacksg
mov ss,ax
mov sp,10
mov bx,0
mov di,0
mov si,0
mov cx,21
s:
mov ax,[bx+0+di]
mov es:[si+0],ax
mov ax,[bx+2+di]
mov es:[si+2],ax
add bx,84
mov ax,[bx+0+di]
mov es:[si+5],ax
mov dx,[bx+2+di]
mov es:[si+7],dx
push ax
push dx
push di
mov dx,0
mov ax,di
mov di,2
div di
mov di,ax
add bx,84
mov ax,[bx+di]
mov es:[si+0ah],ax
pop di
pop dx
pop ax
div word ptr es:[si+0ah]
mov es:[si+0dh],ax
mov bx,0
add di,4
add si,10h
loop s
mov ax,4c00h
int 21h
codesg ends
end start
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