python中如何判断一个变量的数据类型？(原创)

import types

type(x) is types.IntType # 判断是否int 类型

type(x) is types.StringType #是否string类型

.........

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超级恶心的模式，不用记住types.StringType

import types

type(x) == types(1) # 判断是否int 类型

type(x) == type('a') #是否string类型

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使用内嵌函数：

isinstance (

object, classinfo )

Return true if the object
argument is an instance
of the classinfo
argument, or of a (direct or indirect)
subclass thereof. Also return true if classinfo
is a type
object and object
is an object of that type. If object
is not a class instance or an object of the given type, the function
always returns false. If classinfo
is neither a class
object nor a type object, it may be a tuple of class or type objects,
or may recursively contain other such tuples (other sequence types are
not accepted). If classinfo
is not a class, type, or
tuple of classes, types, and such tuples, a TypeError
exception is raised. Changed in version
2.2: Support for a tuple of type information was added.

Python可以得到一个对象的类型 ，利用type函数：

>>>lst = [1, 2, 3]

>>>type(lst)

<type 'list'>

不仅如此，还可以利用isinstance函数，来判断一个对象是否是一个已知的类型。

isinstance说明如下:

isinstance(object, class-or-type-or-tuple) -> bool

Return whether an object is an instance of a class or of a subclass
thereof.

With a type as second argument, return whether that is the object's
type.

The form using a tuple, isinstance(x, (A, B, ...)), is a shortcut
for

isinstance(x, A) or isinstance(x, B) or ... (etc.).

其第一个参数为对象，第二个为类型名或类型名的一个列表。其返回值为布尔型。若对象的类型与参数二的类型相同则返回True。若参数二为一个元组，
则若对象类型与元组中类型名之一相同即返回True。

>>>isinstance(lst, list)

Trueisinstance(lst, (int, str, list))

True

>>>isinstance(lst, (int, str, list))

True