您的位置:首页 > 运维架构 > Linux

[转] 使用Python写Linux的守护进程(daemon)

2009-09-27 22:00 1026 查看

A simple unix/linux daemon in Python

http://www.jejik.com/articles/2007/02/a_simple_unix_linux_daemon_in_python/

by Sander Marechal

I've
written a simple Python class for creating daemons on unix/linux
systems. It was pieced together for various other examples, mostly
corrections to various Python Cookbook
articles and a couple of examples posted to the Python mailing lists.
It has support for a pidfile to keep track of the process. I hope it's
useful to someone.

Below is the Daemon class. To use it, simply subclass it and implement the run() method.

import sys, os, time, atexit
from signal import SIGTERM
class Daemon:
"""
A generic daemon class.

Usage: subclass the Daemon class and override the run() method
"""
def __init__(self, pidfile, stdin='/dev/null', stdout='/dev/null', stderr='/dev/null'):
self.stdin = stdin
self.stdout = stdout
self.stderr = stderr
self.pidfile = pidfile

def daemonize(self):
"""
do the UNIX double-fork magic, see Stevens' "Advanced
Programming in the UNIX Environment" for details (ISBN 0201563177) http://www.erlenstar.demon.co.uk/unix/faq_2.html#SEC16 """
try:
pid = os.fork()
if pid > 0:
# exit first parent
sys.exit(0)
except OSError, e:
sys.stderr.write("fork #1 failed: %d (%s)/n" % (e.errno, e.strerror))
sys.exit(1)

# decouple from parent environment
os.chdir("/")
os.setsid()
os.umask(0)

# do second fork
try:
pid = os.fork()
if pid > 0:
# exit from second parent
sys.exit(0)
except OSError, e:
sys.stderr.write("fork #2 failed: %d (%s)/n" % (e.errno, e.strerror))
sys.exit(1)

# redirect standard file descriptors
sys.stdout.flush()
sys.stderr.flush()
si = file(self.stdin, 'r')
so = file(self.stdout, 'a+')
se = file(self.stderr, 'a+', 0)
os.dup2(si.fileno(), sys.stdin.fileno())
os.dup2(so.fileno(), sys.stdout.fileno())
os.dup2(se.fileno(), sys.stderr.fileno())

# write pidfile
atexit.register(self.delpid)
pid = str(os.getpid())
file(self.pidfile,'w+').write("%s/n" % pid)

def delpid(self):
os.remove(self.pidfile)
def start(self):
"""
Start the daemon
"""
# Check for a pidfile to see if the daemon already runs
try:
pf = file(self.pidfile,'r')
pid = int(pf.read().strip())
pf.close()
except IOError:
pid = None

if pid:
message = "pidfile %s already exist. Daemon already running?/n"
sys.stderr.write(message % self.pidfile)
sys.exit(1)

# Start the daemon
self.daemonize()
self.run()
def stop(self):
"""
Stop the daemon
"""
# Get the pid from the pidfile
try:
pf = file(self.pidfile,'r')
pid = int(pf.read().strip())
pf.close()
except IOError:
pid = None

if not pid:
message = "pidfile %s does not exist. Daemon not running?/n"
sys.stderr.write(message % self.pidfile)
return # not an error in a restart
# Try killing the daemon process
try:
while 1:
os.kill(pid, SIGTERM)
time.sleep(0.1)
except OSError, err:
err = str(err)
if err.find("No such process") > 0:
if os.path.exists(self.pidfile):
os.remove(self.pidfile)
else:
print str(err)
sys.exit(1)
def restart(self):
"""
Restart the daemon
"""
self.stop()
self.start()
def run(self):
"""
You should override this method when you subclass Daemon. It will be called after the process has been
daemonized by start() or restart().
"""


And here is an example implementation. It implements the daemon as well
as it's controlling client. Simply invoke this script with start, stop
or restart as it's first argument.

#!/usr/bin/env python
import sys, time
from daemon import Daemon
class MyDaemon(Daemon):
def run(self):
while True:
time.sleep(1)
if __name__ == "__main__":
daemon = MyDaemon('/tmp/daemon-example.pid')
if len(sys.argv) == 2:
if 'start' == sys.argv[1]:
daemon.start()
elif 'stop' == sys.argv[1]:
daemon.stop()
elif 'restart' == sys.argv[1]:
daemon.restart()
else:
print "Unknown command"
sys.exit(2)
sys.exit(0)
else:
print "usage: %s start|stop|restart" % sys.argv[0]
sys.exit(2)


That's it! I hope this is of some use to someone. Happy coding!
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: