Python入门的36个例子 之 19 -> List

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# 022
listNum1 = [1, 3]
listNum2 = [2, 4]
listStr1 = ['a', 'c']
listStr2 = ['b', 'd']
# 列表的合并
list1 = listNum1 + listStr1
for ele in list1:
print ele
print '/n'
# 判断列表中是否包含某元素
print 'b' in list1
print 1 in list1
# 删除某个元素
for ele in list1:
print ele
del list1[1]
for ele in list1:
print ele
print '/n'
# 对列表进行排序
list1 = listNum1 + listNum2 + listStr1 + listStr2
for ele in list1:
print ele
print '/n'
list1.sort()
for ele in list1:
print ele
print '/n'
# 对列表进行倒排序
list1 = listNum1 + listNum2 + listStr1 + listStr2
for ele in list1:
print ele
print '/n'
list1.sort(reverse = True)
for ele in list1:
print ele
print '/n'
# 对列表进行逆序
list1 = listNum1 + listNum2 + listStr1 + listStr2
for ele in list1:
print ele
print '/n'
list1.reverse()
for ele in list1:
print ele
print '/n'
# 删除列表中连续的一部分
list2 = listNum1 + listNum2 + listStr1 + listStr2
list1 = list2
list1.sort()
for ele in list1:
print ele
print '/n'
del list1[0:2]
for ele in list1:
print ele
print '/n'
# Python中列表比较的是值而不是引用
list3 = [1, 3, 'a', 'c']
list4 = listNum1 + listStr1
print list3 == list4, '/n'
# 列表竟然可以比较大小
list5 = ['b', 'c']
list6 = ['a', 'z']
print list5 > list6, '/n'
# 提取元素
list1 = listNum1 + listNum2 + listStr1 + listStr2
print list1
print list1[7]
print list1[0:4]
# 列表的拼接
list1 = [1,2,3]
list2 = [2,3,4]
list1 += list2
print list1, '/n'
# 列表的翻倍
list1 = [1,2,3]
i = 3
list1 *= i
print list1
# 添加元素的两种方法
list1 = [1,2,3]
list1 += [4]
print list1
list1 = [1,2,3]
list1.append(4)
print list1
# 取得元素个数的方法
list1 = [1,2,3]
print len(list1)
# 取得特定元素的个数
list1 = [1,2,2,3,4,4,4]
print list1.count(2)
print list1.count(4), '/n'
# 在列表中寻找特定的元素
list1 = ['a', 'b', 'c', 'a', 'b', 'c', 'a']
print list1.index('a')
print list1.index('a', 1)
# 在指定位置插入元素
list1 = ['我', '爱', '你']
for ele in list1:
print ele,
print '/n'
list1.insert(2, '不')
list1.insert(3, '爱')
for ele in list1:
print ele,
print '/n'
# 将最后放入的元素弹出
list1 = ['dudu', 'gogo', 'lulu']
print list1
list1.pop()
print list1
print list1.pop()
# 删除第一个匹配的元素
list1 = ['dudu', 'gogo', 'lulu', 'gogo']
print list1
list1.remove('gogo')
print list1

output：

1

3

a

c

False

True

1

3

a

c

1

a

c

1

3

2

4

a

c

b

d

1

2

3

4

a

b

c

d

1

3

2

4

a

c

b

d

d

c

b

a

4

3

2

1

1

3

2

4

a

c

b

d

d

b

c

a

4

2

3

1

1

2

3

4

a

b

c

d

3

4

a

b

c

d

True

True

[1, 3, 2, 4, 'a', 'c', 'b', 'd']

d

[1, 3, 2, 4]

[1, 2, 3, 2, 3, 4]

[1, 2, 3, 1, 2, 3, 1, 2, 3]

[1, 2, 3, 4]

[1, 2, 3, 4]

3

2

3

0

3

我 爱 你

我 爱 不 爱 你

['dudu', 'gogo', 'lulu']

['dudu', 'gogo']

gogo

['dudu', 'gogo', 'lulu', 'gogo']

['dudu', 'lulu', 'gogo']