编引用之swap()---高手帮忙写下笔记，还有解决一下问题，谢谢了

#include <iostream>

using namespace std;

void swap(int &x,int &y);

int main()

{

int x=5,y=10;

cout<<"main.before swap. x: "<<x<<" y: "<<y<<endl;

swap(x,y); //为什么和原型不一样哦？？？？

cout<<"main.after swap, x: "<<x<<" y: "<<y<<endl;

return 0;

}

void swap(int &rx,int &ry) //这里到底是什么意思？？

{

int temp;

cout<<"swap.before swap. rx: "<<rx<<" ry: "<<ry<<endl;

temp=rx;

rx=ry;

ry=temp;

cout<<"swap.before swap. rx: "<<rx<<" ry: "<<ry<<endl;

}