使用Sqlite出现undefined reference to `sqlite3_open'错误的解决

假设你已经正确编译和安装了Sqlite，写个测试程序来测试：

#include <stdlib.h>

#include <stdio.h>

#include "sqlite3.h"

int main(void)

{

sqlite3 *db=NULL;

char *zErrMsg = 0;

int rc;

rc=sqlite3_open("test1.db",&db);

if(rc)

{

fprintf(stderr,"Can't open database: %s\n",sqlite3_errmsg(db));

sqlite3_close(db);

exit(1);

}

else printf("open mydata successfully!\n");

sqlite3_close(db);

return 0;

}

用GCC来编译的时候总是会出现错误，编译的命令如下

gcc -static -o hello -lsqlite3 -L /usr/local/lib -I/usr/local/include hello.c

错误信息如下

/tmp/ccKeKpX9.o(.text+0x37): In function `main':

: undefined reference to `sqlite3_open'

/tmp/ccKeKpX9.o(.text+0x51): In function `main':

: undefined reference to `sqlite3_errmsg'

/tmp/ccKeKpX9.o(.text+0x73): In function `main':

: undefined reference to `sqlite3_close'

/tmp/ccKeKpX9.o(.text+0x9b): In function `main':

: undefined reference to `sqlite3_close'

collect2: ld returned 1 exit status

那么，恭喜你中招了。错误根本不在SQLITE也不在你的程序，而在GCC。Gcc的编译参数是有顺序的。正确的编译命令是：

gcc -o hello -L /usr/local/lib -I/usr/local/include -static hello.c -lsqlite3

说实话，这么的一个小问题困扰了我一天的时间！真是菜啊~~~~~~