用DataSet生成指定格式的XML

最近用FLASH调用DataSet生成的XML发现DataSet的XML都有固定格式,网上也没有太好的方法,于是自己写了下给大家参考

protected void Page_Load(object sender, EventArgs e)

{

TBLL.TSlide slidebll = new TBLL.TSlide();

DataSet ds = slidebll.GetAllList();

XmlDataDocument xdd = SetItemsCountAttribute(ds);

Response.Clear();

xdd.Save(Response.OutputStream);

Response.End();

}

private XmlDataDocument SetItemsCountAttribute(DataSet ds)

{

try

{

XmlDataDocument xmlDoc;

int ItemCount = 0;

ds.DataSetName = strRootNodeName;

ds.EnforceConstraints = false;

xmlDoc = new XmlDataDocument();

XmlNode xmlDocNode = xmlDoc.CreateXmlDeclaration("1.0", "UTF-8", null);

xmlDoc.AppendChild(xmlDocNode);

XmlNode viewer = xmlDoc.CreateElement("viewer");

XmlAttribute interval = xmlDoc.CreateAttribute("interval");

interval.Value = "4000";

viewer.Attributes.Append(interval);

XmlAttribute isRandom = xmlDoc.CreateAttribute("isRandom");

isRandom.Value = "1";

viewer.Attributes.Append(isRandom);

xmlDoc.AppendChild(viewer);

for (int i = 0; i < ds.Tables[0].Rows.Count; i++)

{

XmlNode item = xmlDoc.CreateElement("item");

XmlAttribute title = xmlDoc.CreateAttribute("title");

title.Value = ds.Tables[0].Rows[i]["Title"].ToString();

item.Attributes.Append(title);

XmlAttribute img = xmlDoc.CreateAttribute("img");

img.Value = ds.Tables[0].Rows[i]["ImgUrl"].ToString();

item.Attributes.Append(img);

XmlAttribute url = xmlDoc.CreateAttribute("url");

url.Value = ds.Tables[0].Rows[i]["LinkUrl"].ToString();

item.Attributes.Append(url);

XmlAttribute target = xmlDoc.CreateAttribute("target");

target.Value = "_blank";

item.Attributes.Append(target);

viewer.AppendChild(item);

}

return xmlDoc;

}

catch (Exception e)

{

string strMsg = e.Message;

return null;

}

}