您的位置:首页 > 产品设计 > UI/UE

java continue标签的一个技巧性例子

2006-10-20 17:51 162 查看
public class Continue
{
public static void main(String [] args)
{
L1:
for(int i = 0; i < 5; ++i)
{

if(i == 2)
{System.out.println(i);
continue L1; }
L2:
for(int j = 0; j < 5; ++j)
{
if(i == 3 && j == 3)
{System.out.println(j);
continue L1; }
else
if(j == 4)
{System.out.println(j);
continue L2; }

System.out.println("i == " + i + " j == " + j);
}

if(i == 5)
break;
}
}
}

i == 0 j == 0
i == 0 j == 1
i == 0 j == 2
i == 0 j == 3
4
i == 1 j == 0
i == 1 j == 1
i == 1 j == 2
i == 1 j == 3
4
2
i == 3 j == 0
i == 3 j == 1
i == 3 j == 2
3
i == 4 j == 0
i == 4 j == 1
i == 4 j == 2
i == 4 j == 3
4
continue label,跳到label处,并且跳过continue的外层迭代
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: