在ASP.NET中实现多文件上传

在ASP.NET中实现多文件上传
在以前的Web应用中，上传文件是个很麻烦的事，现在有了.NET，文件上传变得轻而易举。下面的这个例子实现了多文件上传功能。可以动态添加输入表单，上传的文件数量没有限制。代码如下：

查看例子

MultiUpload.aspx
<%@ Page Language="vb" AutoEventWireup="false" Codebehind="MultiUpload.aspx.vb"
Inherits="aspxWeb.MultiUpload" %>



多文件上传

function addFile()
{
var str = ''
document.getElementById('MyFile').insertAdjacentHTML("beforeEnd",str)
}




















后代码：MultiUpload.aspx.vb
Public Class MultiUpload
Inherits System.Web.UI.Page
Protected WithEvents Upload As System.Web.UI.WebControls.Button
Protected WithEvents MyTitle As System.Web.UI.WebControls.Label
Protected WithEvents strStatus As System.Web.UI.WebControls.Label
#Region " Web Form Designer Generated Code "
'This call is required by the Web Form Designer.
Private Sub InitializeComponent()
End Sub
Private Sub Page_Init(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Init
'CODEGEN: This method call is required by the Web Form Designer
'Do not modify it using the code editor.
InitializeComponent()
End Sub
#End Region
Private Sub Page_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
MyTitle.Text = "

多文件上传

"
Upload.Text = "开始上传"
If (Me.IsPostBack) Then Me.SaveImages()
End Sub
Private Function SaveImages() As System.Boolean
'遍历File表单元素
Dim files As System.Web.HttpFileCollection = System.Web.HttpContext.Current.Request.Files
'状态信息
Dim strMsg As New System.Text.StringBuilder("上传的文件分别是：")
Dim iFile As System.Int32
Try
For iFile = 0 To files.Count - 1
'检查文件扩展名字
Dim postedFile As System.Web.HttpPostedFile = files(iFile)
Dim fileName, fileExtension As System.String
fileName = System.IO.Path.GetFileName(postedFile.FileName)
If Not (fileName = String.Empty) Then
fileExtension = System.IO.Path.GetExtension(fileName)
strMsg.Append("上传的文件类型：" + postedFile.ContentType.ToString() + "
")
strMsg.Append("客户端文件地址：" + postedFile.FileName + "
")
strMsg.Append("上传文件的文件名：" + fileName + "
")
strMsg.Append("上传文件的扩展名：" + fileExtension + "
")
'可根据扩展名字的不同保存到不同的文件夹
postedFile.SaveAs(System.Web.HttpContext.Current.Request.MapPath("images/") + fileName)
End If
Next
strStatus.Text = strMsg.ToString()
Return True
Catch Ex As System.Exception
strStatus.Text = Ex.Message
Return False
End Try
End Function
End Class