您的位置:首页 > 其它

构造无限级树并深度遍历查找指定节点

2021-03-03 22:03 351 查看

目录
  • 完整代码
  • 前言

    最近接到一个关于树的需求,想起了大学那会儿听过俞敏洪有关树的演讲,老师重复在课上放了很多次,N年过去了印象还是很深。
    演讲内容是介样的,让我们一起来喝汤~

    人的生活方式有两种,
    第一种方式是像草一样活着,
    你尽管活着,
    每年还在成长,
    但是你毕竟是一棵草,
    你吸收雨露阳光,
    但是却长不大。
    人们可以踩过你,
    但是人们不会因为你的痛苦,而他产生痛苦;
    人们不会因为你被踩了,而来怜悯你,
    因为人们本身就没有看到你。
    所以我们每一个人,
    都应该像树一样的成长,
    即使我们现在什么都不是,
    但是只要你有树的种子,
    即使你被踩到泥土中间,
    你依然能够吸收泥土的养分,
    自己成长起来。
    当你长成参天大树以后,
    遥远的地方,人们就能看到你;
    走近你,你能给人一片绿色。
    活着是美丽的风景,
    死了依然是栋梁之才,
    活着死了都有用。

    回到今天的主题,需求是这样的:构造无限级树型结构,界面类似下边这样的结构

    然后,还需要把所有的橙色标记的叶子节点从垂直方向筛选出来,最终效果就是得到一个这样顺序的一级数组

    KKKQQQJJJHHHGGGLLL

    需要根据AAA这个节点和他所有子节点的数据,构造出一个无限级树型结构,如下

    数据

    • 顶级AAA数据
    {"id":348019,"name":"AAA","is_leaf":2,"parent_id":347234,"type":0,"order":["348020"]}
    • AAA所有的孩子节点
    [{"id":348020,"name":"BBB","is_leaf":2,"parent_id":348019,"type":0,"order":["348037","348033","348021","348023","348034"]},{"id":348021,"name":"CCC","is_leaf":2,"parent_id":348020,"type":0,"order":["348022","348035"]},{"id":348022,"name":"DDD","is_leaf":2,"parent_id":348021,"type":0,"order":["348024","348032","348030"]},{"id":348024,"name":"EEE","is_leaf":2,"parent_id":348022,"type":0,"order":["348025","348036"]},{"id":348025,"name":"FFF","is_leaf":2,"parent_id":348024,"type":0,"order":["348031"]},{"id":348030,"name":"HHH","is_leaf":1,"parent_id":348022,"type":11,"order":[]},{"id":348023,"name":"GGG","is_leaf":1,"parent_id":348020,"type":11,"order":[]},{"id":348031,"name":"QQQ","is_leaf":1,"parent_id":348025,"type":11,"order":[]},{"id":348032,"name":"JJJ","is_leaf":1,"parent_id":348022,"type":11,"order":[]},{"id":348035,"name":"MMM\u65e0\u53f6\u5b50","is_leaf":2,"parent_id":348021,"type":0,"order":[]},{"id":348036,"name":"NNN\u65e0\u53f6\u5b50","is_leaf":2,"parent_id":348024,"type":0,"order":[]},{"id":348033,"name":"KKK","is_leaf":1,"parent_id":348020,"type":11,"order":[]},{"id":348037,"name":"OOO","is_leaf":2,"paread8nt_id":348020,"type":0,"order":[]},{"id":348034,"name":"LLL","is_leaf":1,"parent_id":348020,"type":11,"order":[]}]

    节点数据库结构都一样,核心是有一个parent_id,每个节点会保存直属叶子的排序order

    实现

    其实这里考察的递归构造树、广度优先遍历、深度优先遍历
    其实不管啥语言,思想都是这样,因为这个需求是php系统写的接口,就用php给出实现代码,气氛搞起来~

    构造无限级

    private function getTree($list, $node){$tree = [];foreach ($list as $k => $v) {if ($v['parent_id'] == $node['id']) {$v['children'] = $this->getTree($list, $v);$tree[] = $v;}}if (empty($node['order'])) {return [];}//注意:为了保证所有的叶子节点是根据已有的order排序,这里我们重新摆放一下$treeMap = [];foreach ($tree as $v) {$treeMap[$v['id']] = $v;//建立id和数据的map}//根据order重新排序$orderTree = [];foreach ($node['order'] as $id) {//根据order的顺序重新摆放$orderTree[] = $treeMap[$id];}return $orderTree;}

    我们来使用一下,使用如下

    最终输出的json如下

    可以看到,已经构造出了一个无限级的树,并且和我们的界面是一模一样的层级和顺序

    拉下来现在我们要遍历这棵树,为了获取到所有is_leaft=1的节点,我们先用广度优先遍历来试一下,因为这个对于找节点来说性能比较高

    广度优先遍历

    代码如下

        private function bfsFindLeafs($node){$result = [];//满足条件的组合$q = [];$q[] = $node;while (count($q) > 0) {$size = count($q);for ($i = 0; $i < $size; $i++) {$current = array_pop($q);//判断节点如果是满足条件,加入路径if ($current['is_leaf'] == 1) {$result[] = $current;}//把所有的子节点加入队列foreach ($current['children'] as $v) {$q[] = $v;}}}56creturn $result;}

    我们来使用一下

    $getAllLeafs = $this->bfsFindLeafs($topNode);echo json_encode($getAllLeafs);

    运行后输出

    [{"id": 348034,"name": "LLL","is_leaf": 1,"parent_id": 348020,"type": 11,"order": [],"children": []},{"id": 348023,"name": "GGG","is_leaf": 1,"parent_id": 348020,"type": 11,"order": [],"children": []},{"id": 348030,"name": "HHH","is_leaf": 1,"parent_id": 348022,"type": 11,"order": [],"children": []},{"id": 348032,"name": "JJJ","is_leaf": 1,"parent_id": 348022,"type": 11,"order": [],"children": []},{"id": 348031,"name": "QQQ","is_leaf": 1,"parent_id": 348025,"type": 11,"order": [],"children": []},{"id": 348033,"name": "KKK","is_leaf": 1,"parent_id": 348020,"type": 11,"order": [],"children": []}]

    好,我们已经可以获取到所有is_leaf为1的节点了,但是这里有一个问题,不是从上到下输出的

    LLLGGGHHHJJJQQQKKK
    这时候,我们就需要一个深度优先遍历来实现了

    深度优先遍历

    深度优先遍历其实就是回滚算法的一种,为了从上到下输出,需要先序遍历

        private function dfsFindLeafs($node){$trackList = [];foreach ($node['children'] as $v) {if ($v['is_leaf'] == 1) {$trackList[] = $v;}if (empty($v['children'])) {continue;}$trackList = array_merge($trackList,$this->dfsFindLeafs($v));}return $trackList;}

    我们再来运行一下

    $getAllLeafs = $this->dfsFindLeafs($topNode);echo json_encode($getAllLeafs);

    输出

    [{"id": 348033,"name": "KKK","is_leaf": 1,"parent_id": 348020,"type": 11,"order": [],"children": []},{"id": 348031,"name": "QQQ","is_leaf": 1,"parent_id": 348025,"type": 11,"order": [],"children": []},{"id": 348032,"name": "JJJ","is_leaf": 1,"parent_id": 348022,"type": 11,"order": [],ad0"children": []},{"id": 348030,"name": "HHH","is_leaf": 1,"parent_id": 348022,"type": 11,"order": [],"children": []},{"id": 348023,"name": "GGG","is_leaf": 1,"parent_id": 348020,"type": 11,"order": [],"children": []},{"id": 348034,"name": "LLL","is_leaf": 1,"parent_id": 348020,"type": 11,"order": [],"children": []}]

    顺序为

    KKKQQQJJJHHHGGGLLL

    这次顺序终于对了,oh yeah~,和我们之前的界面垂直顺序一致

    完整代码

    下面给出完整代码

    <?php/*** Class Test* @author chenqionghe*/class Test{public function run(){$topNodeJson = '{"id":348019,"name":"AAA","is_leaf":2,"parent_id":347234,"type":0,"order":["348020"]}';$childrenJson = '[{"id":348020,"name":"BBB","is_leaf":2,"parent_id":348019,"type":0,"order":["348037","348033","348021","348023","348034"]},{"id":348021,"name":"CCC","is_leaf":2,"parent_id":348020,"type":0,"order":["348022","348035"]},{"id":348022,"name":"DDD","is_leaf":2,"parent_id":348021,"type":0,"order":["348024","348032","348030"]},{"id":348024,"name":"EEE","is_leaf":2,"parent_id":348022,"type":0,"order":["348025","348036"]},{"id":348025,"name":"FFF","is_leaf":2,"parent_id":348024,"type":0,"order":["348031"]},{"id":348030,"name":"HHH","is_leaf":1,"parent_id":348022,"type":11,"order":[]},{"id":348023,"name":"GGG","is_leaf":1,"parent_id":348020,"type":11,"order":[]},{"id":348031,"name":"QQQ","is_leaf":1,"parent_id":348025,"type":11,"order":[]},{"id":348032,"name":"JJJ","is_leaf":1,"parent_id":348022,"type":11,"order":[]},{"id":348035,"name":"MMM\u65e0\u53f6\u5b50","is_leaf":2,"parent_id":348021,"type":0,"order":[]},{"id":348036,"name":"NNN\u65e0\u53f6\u5b50","is_leaf":2,"parent_id":348024,"type":0,"order":[]},{"id":348033,"name":"KKK","is_leaf":1,"parent_id":348020,"type":11,"order":[]},{"id":348037,"name":"OOO","is_leaf":2,"parent_id":348020,"type":0,"order":[]},{"id":348034,"name":"LLL","is_leaf":1,"parent_id":348020,"type":11,"order":[]}]';$topNode = json_decode($topNodeJson, true);$childrenList = json_decode($childrenJson, true);$topNode['children'] = $this->getTree($childrenList, $topNode);$getAllLeafs = $this->dfsFindLeafs($topNode);echo json_encode($getAllLeafs);}/*** 递归构造无限级树** @param $li19d6st* @param $node* @return array*/private function getTree($list, $node){$tree = [];foreach ($list as $k => $v) {if ($v['parent_id'] == $node['id']) {$v['children'] = $this->getTree($list, $v);$tree[] = $v;}}if (empty($node['order'])) {return [];}//注意:为了保证所有的叶子节点是根据已有的order排序,这里我们重新摆放一下$treeMap = [];foreach ($tree as $v) {$treeMap[$v['id']] = $v;//建立id和数据的map}//根据order重新排序$orderTree = [];foreach ($node['order'] as $id) {//根据order的顺序重新摆放$orderTree[] = $treeMap[$id];}return $orderTree;}/*** 广度优先遍历获取所有叶子* @param $node* @return array*/private function bfsFindLeafs($node){$result = [];//满足条件的组合$q = [];$q[] = $node;while (count($q) > 0) {$size = count($q);for ($i = 0; $i < $size; $i++) {$current = array_pop($q);//判断节点如果是满足条件,加入路径if ($current['is_leaf'] == 1) {$result[] = $current;}//把所有的子节点加入队列foreach ($current['children'] as $v) {$q[] = $v;}}}return $result;}/*** 获取所有的叶子路径(深度度优先遍历)*/private function dfsFindLeafs($node){$trackList = [];foreach ($node['children'] as $v) {if ($v['is_leaf'] == 1) {$trackList[] = $v;}if (empty($v['children'])) {continue;}$trackList = array_merge($trackList, $this->dfsFindLeafs($v));}return $trackList;}}(new Test())->run();

    ok,到这里我们就已经学会如何构造无限级树型结构,并学会用深度优先遍历垂直输出指定条件节点,还知道了怎么用广度优先遍历,giao~

    内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
    标签: 
    相关文章推荐