[系列] Go - time.RFC3339 时间格式化

在开发过程中，我们有时会遇到这样的问题，将

2020-11-08T08:18:46+08:00

2020-11-08 08:18:46

解决这个问题，最好不要用字符串截取，或者说字符串截取是最笨的方法，这应该是时间格式化的问题。

我们先看一下 golang time 包中支持的 format 格式：

const (
ANSIC       = "Mon Jan _2 15:04:05 2006"
UnixDate    = "Mon Jan _2 15:04:05 MST 2006"
RubyDate    = "Mon Jan 02 15:04:05 -0700 2006"
RFC822      = "02 Jan 06 15:04 MST"
RFC822Z     = "02 Jan 06 15:04 -0700" // RFC822 with numeric zone
RFC850      = "Monday, 02-Jan-06 15:04:05 MST"
RFC1123     = "Mon, 02 Jan 2006 15:04:05 MST"
RFC1123Z    = "Mon, 02 Jan 2006 15:04:05 -0700" // RFC1123 with numeric zone
RFC3339     = "2006-01-02T15:04:05Z07:00"
RFC3339Nano = "2006-01-02T15:04:05.999999999Z07:00"
Kitchen     = "3:04PM"
// Handy time stamps.
Stamp      = "Jan _2 15:04:05"
StampMilli = "Jan _2 15:04:05.000"
StampMicro = "Jan _2 15:04:05.000000"
StampNano  = "Jan _2 15:04:05.000000000"
)

我们找到了

RFC3339

RFC3339ToCSTLayout

package timeutil

import "time"

var (
cst *time.Location
)

// CSTLayout China Standard Time Layout
const CSTLayout = "2006-01-02 15:04:05"

func init() {
var err error
if cst, err = time.LoadLocation("Asia/Shanghai"); err != nil {
panic(err)
}
}

// RFC3339ToCSTLayout convert rfc3339 value to china standard time layout
func RFC3339ToCSTLayout(value string) (string, error) {
ts, err := time.Parse(time.RFC3339, value)
if err != nil {
return "", err
}

return ts.In(cst).Format(CSTLayout), nil
}

运行一下

RFC3339Str := "2020-11-08T08:18:46+08:00"
cst, err := timeutil.RFC3339ToCSTLayout(RFC3339Str)
if err != nil {
fmt.Println(err)
}
fmt.Println(cst)

输出：

2020-11-08 08:18:46

小结

同理，若遇到

RFC3339Nano

RFC822

RFC1123

time.Parse()