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oracle的decode函数

2020-06-06 07:14 639 查看

一、decode函数的使用方法
decode()函数,它将输入数值与函数中的参数列表相比较,根据输入值返回一个对应值。函数的参数列表是由若干数值及其对应结果值组成的若干序偶形式。当然,如果未能与任何一个实参序偶匹配成功,则函数也有默认的返回值。
语法结构如下

decode (expression, value1, result1, value2, result2, ..., valuen, resultn, default)

根据expression表达式进行判断,如果expression返回的值等于value1,则返回result1,如果expression返回的值等于等于value2,则返回result2,如果都不等于,则返回default值,如果没有定义default,则返回空值。

二、示例
创建表

create table student_score(
name varchar2(30),
subject varchar2(20),
score number(4,1)
);

插入数据

insert into student_score (name,subject,score) values ('张三','中文',90);
insert into student_score (name,subject,score) values ('张三','数学',80);
insert into student_score (name,subject,score) values ('张三','外语',89);
insert into student_score (name,subject,score) values('李四','中文',96);
insert into student_score (name,subject,score) values('李四','数学',86);
insert into student_score (name,subject,score) values('李四','外语',76);
insert into student_score (name,subject,score) values('王五','中文',92);
insert into student_score (name,subject,score) values('王五','数学',82);
insert into student_score (name,subject,score) values('王五','外语',72);

查询

--如果学科为中文,则返回分数,否则返回0
select name,subject,decode(subject,'中文',score,0) from student_score;
--统计中文学科的分数
select name,sum(decode(subject,'中文',score,0)) as 中文 from student_score group by name;
--使用decode函数进行行转列
select name,
sum(decode(subject, '中文', score, 0)) as 中文,
sum(decode(subject, '数学', score, 0)) as 数学,
sum(decode(subject, '外语', score, 0)) as 外语
from student_score
group by name;
--使用case when
select name,
sum(case
when subject = '中文' then
nvl(score, 0)
else
0
end) 中文,
sum(case
when subject = '数学' then
nvl(score, 0)
else
0
end) 数学,
sum(case
when subject = '外语' then
nvl(score, 0)
else
0
end) 外语
from student_score
group by name
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